Java program to find first two maximum numbers in an array,using single loop without sorting array.

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December 27, 2011 at 12:11 PM

import java.util.*; class ArrayExample { public static void main(String[] args) { int secondlargest = 0; int largest = 0; Scanner input = new Scanner(System.in); System.out.println("Enter array values: "); int arr[] = new int[5]; for (int i = 0; i < arr.length; i++) { arr[i] = input.nextInt(); if (largest < arr[i]) { secondlargest = largest; largest = arr[i]; } if (secondlargest < arr[i] && largest != arr[i]) secondlargest = arr[i]; } System.out.println("Largest number is: " + largest); System.out.println("Second Largest number is: " + secondlargest); } }

September 10, 2012 at 2:36 PM

package com.java.interview.array;

import java.util.Scanner;

public class TwoLargestElementsOfArray {

/** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int secondlargest = 0; int largest = 0; int size = 0; Scanner input = new Scanner(System.in); System.out.println("Enter the size of array: "); size = input.nextInt(); int arr[] = new int[size]; if (size < 2) System.out.println("Please enter the valid size of array"); System.out.println("Enter array values: "); for (int i = 0; i < arr.length; i++) { arr[i] = input.nextInt(); if (largest < arr[i]) { secondlargest = largest; largest = arr[i]; } if (secondlargest < arr[i] && largest != arr[i]) secondlargest = arr[i]; } System.out.println("Largest number is: " + largest); System.out.println("Second Largest number is: " + secondlargest); }

}

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