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Listing Directory using
Regular expression
This Example describe the way
how to list the directory by using Regularexpression.The steps involved
in replacing a String are described below:
File directorypath = new File("/home/girish/Desktop/Linux"):-it
is the path where my directory is stored.Before running this example
create your own directory and give the path of the directory.
String[] list:-Creates an array named list.
list = directorypath.list():-This method returns array of string including the files and directories in the
directory followed by this abstract pathname.
list = directorypath.list(new DirFilter(args[0])):-This method returns array of string including the files and directories in the
directory followed by this abstract pathname that suits the specified filter.
public
boolean accept(File directorypath, String name):-This method is for
testing if a specified file should be included in a file list.
pattern = Pattern.compile(regex):-This method compiles the regular expression into a pattern.
Listdirectory.java
import java.io.File;
import java.io.FilenameFilter;
import java.util.regex.Pattern;
public class Listdirectory {
public static void main(String[] args) {
File directorypath = new File("/home/girish/Desktop/Linux");
String[] list;
if (args.length == 0)
list = directorypath.list();
else
list = directorypath.list(new DirFilter(args[0]));
for (int i = 0; i < list.length; i++)
System.out.println(list[i]);
}
}
class DirFilter implements FilenameFilter {
private Pattern pattern;
public DirFilter(String regex) {
pattern = Pattern.compile(regex);
}
public boolean accept(File directorypath, String name) {
return pattern.matcher(new File(name).getName()).matches();
}
}
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Output of the program:-
linux.doc
new file~
song
new file
Xmlroseindia.odt |
Download Source Code
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