Core Java| JSP| Servlets| XML| EJB| JEE5| Web Services| J2ME| Glossary| Questions?

Search Tutorials

Latest Questions

no driver
i am having problem connecting to DB2 database fro netbeans: program: import java.sql.*; import java.lang.*; i
min project with vb
i have do the min project with VB Frantend and oracle backend
Some additions for my previous question
This is the question I posted several hours ago: "I'm trying to write a program that has a text field for input, two bu
Writing a GUI program
Hello everyone! I'm trying to write a program that has a text field for input, two buttons and the output text area. A
How to display current date in textbox
Hi guys, I'm really need your help. This is my source code. <% if (status.equals("pending") && penanda==0)
Methods in Java
Hello. Currently i am involved in a group project and we have each been given a specific part of code to create our joi
how to record qvga video using j2me
hello if it is possible how i can record qvga video usin j2me?
how to record qvga video using j2me
hello if it is possible how i can record qvga video usin j2me?
streams
a program which illustrate the use of streams
runtime polymorphism
how run time polymorphism is achieved
All Questions...

Comments

Checking whether a year is leap or not
In this section, you will learn how to checking whether a year is leap or not.

Checking whether a year is leap or not

This tutorial is going to teach you the coding for checking whether a year is a leap year or not. Here, we have taken the year 2000. So define an integer n=2000 in the class "Leapyear" and now apply "if else" condition. As we know leap year is divided by the integer 4 and so applying if condition as n/4=0, then "n" is a leap year. Now in the System.out.println write the message that the year is a leap year. Again applying "else" condition the output will be that the year is not a leap year.

Here is the code of program:


class  Leapyear

{

  public static void main(String[] args) 

  {

    int n=2000;

    if (n%4==0){

    System.out.println("The given year is a leap year");

      }

    else{

    System.out.println("This is not a leap year");

  }

}

}

Download the program:

� View all related tutorials

Related Tags: c file class orm constructor object path struct const value name return instance paths create if send match to bot

Leave your comment:
Name:
Email:
URL:
Title:
Comments:
Enter Code:
	Note: Emails will not be visible or used in any way, and are not required. Please keep comments relevant. Any content deemed inappropriate or offensive may be edited and/or deleted. No HTML code is allowed. Line breaks will be converted automatically. URLs will be auto-linked. Please use BBCode to format your text.

Add This Tutorial To:
Del.icio.us	Digg	Google	Spurl	Blink	Furl	Simpy	Y! MyWeb

Current Comments

4 comments so far (post your own) View All Comments Latest 10 Comments:

This Program Dose Not Meet All The Conditions For A Leap Year...

Posted by Amar on Monday, 09.29.08 @ 13:39pm | #80769

View This Comment Separately

Your leap year example gives false results for the years 1900, 2100 and others.
The leap year rules are:
1. Years that are multiples of 4 are leap years,
except for the following special years.
2. Years that are mutliples of 100 are not leap years, except for the following special years.
3. Years that are multiples 400 are leap years.
Your program does not obey to rule 2.

Posted by Hubert Partl on Wednesday, 01.2.08 @ 16:52pm | #44367

View This Comment Separately

Its very helpful for beginners.

Posted by Monisha agarwal on Sunday, 03.25.07 @ 11:21am | #12652

View This Comment Separately

good example for the biginners

Posted by visakh m g on Friday, 12.1.06 @ 14:12pm | #316

View This Comment Separately

Training Courses