Hibernate persist Method

In this tutorial you will learn about how to use persist method in hibernate.

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Hibernate persist Method

In this tutorial you will learn about how to use persist method in hibernate.

Hibernate's persist() method is used to insert / save the record to the database table. This method is equal to the save() method but, it is different in the case that the save() method can return the id (primary key) value that is generated by the hibernate but the persist() method never returns value to the client.

Example :

Here is a basic example which will demonstrate you how persist() method can be used in Hibernate. For this I am giving a complete source code which can be downloaded. To achieve the solution of our problem at first I have created a table in MySQL named employee with the fields Id, Name and then created a POJO / Persistent class named Employee.java to fetch the persistent object, a hibernate.cfg.xml file that the Hibernate can utilize it to create connection pool and the required environment setup, an employee.hbm.xml file to map an Employee object with table employee. And finally create a simple java file using which we will use persist() method of Hibernate to insert record to the table.

Complete Code :

Employee.java

package roseindia;

public class Employee {
private int id;
private String name;

public Employee()
{

}
public Employee(String name)
{
this.name = name;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}

employee.hbm.xml

<?xml version='1.0'?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">

<hibernate-mapping package="roseindia">
<class name="Employee" table="employee">
<id name="id" type="int" column="Id" >
<generator class="native"/>
</id>
<property name="name">
<column name="Name" />
</property>
</class>
</hibernate-mapping>

hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://192.168.10.13:3306/data
</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">root</property>
<property name="hibernate.connection.pool_size">10</property>
<property name="show_sql">true</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.current_session_context_class">thread</property>
</session-factory>

</hibernate-configuration>

EmpPersist.java

package roseindia;

import java.util.Scanner;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
import org.hibernate.service.ServiceRegistry;
import org.hibernate.service.ServiceRegistryBuilder;

public class EmpPersist {
private static SessionFactory sessionFactory;
private static ServiceRegistry serviceRegistry;

public static void main(String args[]) {

Session session =null;

try
{
try
{
Configuration cfg = new Configuration().addResource("roseindia/employee.hbm.xml").configure();
serviceRegistry = new ServiceRegistryBuilder().applySettings(
cfg.getProperties()).buildServiceRegistry();
sessionFactory = cfg.buildSessionFactory(serviceRegistry);
}
catch(Throwable th)
{
System.err.println("Failed to create sessionFactory object."+ th);
throw new ExceptionInInitializerError(th);
}
session = sessionFactory.openSession();
Employee employee = new Employee();
Transaction tx = session.beginTransaction();
Scanner scan = new Scanner(System.in);
System.out.println("Enter name of Employee : ");
String setEmpName = scan.next();
employee.setName(setEmpName);
session.persist(employee);
System.out.println("Data has been inserted to the table.");
tx.commit();
}
catch(Exception e)
{
System.out.println(e.getMessage());
}
finally
{
session.close();
}
}
}

Output :

1. Table without record

2. When you will execute the java file EmpPersist.java and provide the information looking as on console you will get the output as :

3. When you will provide the info looking at console successfully then the data will be inserted to the table and will look as :

Download Source Code

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Hibernate persist Method

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