# Checking whether a year is leap or not

This tutorial is going to teach you the coding for checking whether a year is a leap year or not.

### Checking whether a year is leap or not

This tutorial is going to teach you the coding for checking whether a year is a leap year or not.

# Checking whether a year is leap or not

This tutorial is going to teach you the coding for checking whether a year is a leap year or not. Here, we have taken the year 2000. So define an integer n=2000 in the class "Leapyear" and now apply "if else" condition. As we know leap year is divided by the integer 4 and so applying if condition as n/4=0, then "n" is a leap year. Now in the System.out.println write the message that the year is a leap year. Again applying "else" condition the output will be that the year is not a leap year.

Here is the code of program:

 ``` class  Leapyear {   public static void main(String[] args)    {   int n=2000;   if (n%4==0){   System.out.println("The given year is a leap year");   }   else{   System.out.println("This is not a leap year");   } } }```

`Download the program:`