# Timer in the code

Pam
Timer in the code
Posted in : Java Beginners

November 23, 2009 at 4:34 PM

Hi Friend,

Try the following:

import java.util.*;

class PrimesCMDLine{
public static void checkPrime(long num){
long i=0;
for ( i = 2; i < num; i++) {
long n = num % i;
if (n == 0) {
System.out.println("Entered number is not Prime!");
break;
}
}
if (i == num) {
System.out.println("Number is Prime!");
}
}

public static void findFactors(long n){
System.out.print("The prime factorization of " + n + " is: ");
for (long i = 2; i <= n / i; i++) {
while (n % i == 0) {

n = n / i;
System.out.print(i + " ");
}
}
if (n > 1) System.out.println(n);
else System.out.println();
}

public static void main(String[] args) throws Exception {
Scanner scan = new Scanner(System.in);
System.out.println("Test");
System.out.println();
System.out.println("p. check prime or not");
System.out.println("f. prime factors");
System.out.println("e. Exit");

boolean quit = false;
do{
System.out.println();
switch(ch) {
case 'p':
System.out.print("Enter number: ");
long num=scan.nextLong();
PrimesCMDLine.checkPrime(num);
break;
case 'f':
long start = System.currentTimeMillis();
System.out.println("Start: " + start);
System.out.print("Enter number: ");
long num1=scan.nextLong();
PrimesCMDLine.findFactors(num1);
long end = System.currentTimeMillis();
System.out.println("End : " + end);
long elapsedTime = end - start;
System.out.println(elapsedTime + " milli seconds");
System.out.println();
break;
case 'e':
quit = true;
break;
default:
System.out.println("Invalid Entry!");
}
}
while (!quit);
}
}

If you got any error or any problem, then send your code.

Thanks

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