Square pattern in java using for loop

Square pattern in java using for loop

please explain the logic to program the following using for loop in Java:

1 3 5 7 9

3 5 7 9 1

5 7 8 1 3

7 9 1 3 5

9 1 3 5 7

View Answers

November 26, 2012 at 12:11 PM

Here is a code that displays the following pattern:

1 3 5 7 9

3 5 7 9 1

5 7 8 1 3

7 9 1 3 5

9 1 3 5 7


public class Pattern {
        public static void main(String[] args) {
                int[] array = {1,3,5,7,9};
                System.out.println("Original array is:");
                printArray(array);
                for(int i=1;i<=4;i++){
                shift(array, 1);
                        printArray(array);
                }
        }

        public static void shift(int[] array, int amount) {
               for (int j = 0; j < amount; j++) {
                        int a = array[0];
                        int i;
                        for (i = 0; i < array.length - 1; i++)
                                array[i] = array[i + 1];
                        array[i] = a;
                }
        }

        public static void printArray(int[] array) {
                for (int x = 0; x < array.length; x++) {
                        System.out.print(array[x] + " ");
                }
                System.out.println();
        }

}

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