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Faisal Ansari
2 Answer(s)      6 years and 8 months ago
Posted in : Java Beginners

How to create .Exe file in jana?

View Answers

February 28, 2011 at 4:17 PM

Java Create exe. file:

import java.util.jar.*;
class OnlyExt implements FilenameFilter{
  String ext;
  public OnlyExt(String ext){
  this.ext="." + ext;
  public boolean accept(File dir,String name){
  return name.endsWith(ext);
public class CreateExe{
public static int buffer = 10240;
protected void create(File exefile, File[] listFiles){
byte b[] = new byte[buffer];
FileOutputStream fout = new FileOutputStream(exefile);
JarOutputStream out = new JarOutputStream(fout, new Manifest());
for(int i = 0; i < listFiles.length; i++){
if(listFiles[i] == null || !listFiles[i].exists()|| listFiles[i].isDirectory())
System.out.println("Adding " + listFiles[i].getName());
JarEntry addFiles = new JarEntry(listFiles[i].getName());

FileInputStream fin = new FileInputStream(listFiles[i]);
int len =, 0, b.length);
if(len <= 0)
out.write(b, 0, len);
System.out.println("Exe File is created successfully.");
} catch (Exception ex){}
public static void main(String[]args){
CreateExe exe=new CreateExe();
FilenameFilter ff = new OnlyExt("class");
File folder = new File("c:/Examples");
File[] files = folder.listFiles(ff);
File file=new File("C:/Examples/Examples.exe");
exe.create(file, files);

February 28, 2011 at 7:48 PM

Sorry sir this program is not working. pl make a simple program.


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