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plz plz give coding for C CO COM COMP COMPU COMPUT COMPUTE COMPUTER & wap to print product of digits (212=212) &wap to compute sum of 1^2+2^2+4^2+8^2+10^2 . coding for:

                 *
                * *
               *   *
                * *
                 *
View Answers

January 10, 2011 at 2:50 PM

Hi Friend,

1)Try the following code:

import java.util.*;
class  StringExample3
{
    public static void main(String[] args) 
    {
        Scanner input=new Scanner(System.in);
        System.out.print("Enter word: ");
        String st=input.next();
        for(int i=0;i<=st.length();i++){
            int j=i+1;
            System.out.println(st.substring(0,i));
        }
    }
}

Thanks


January 10, 2011 at 3:01 PM

Hi FRiend,

2)Try the following code:

import java.util.*;
class ProductOfDigits 
{
    public static void main(String[] args) 
    {
        Scanner input=new Scanner(System.in);
        System.out.print("Enter multidigit number: ");
        long no=input.nextLong();
        long p=1,i=0;
        while(no>0)
        {   
        i=no%10;
        p=p*i;
        no=no/10;
       }
       System.out.println("Product of digits: "+p);
    }
}

Thanks


January 10, 2011 at 3:08 PM

Hi Friend,

3)Try the following code:

class FindSum 
{
    public static void main(String[] args) 
    {
        double sum=Math.pow(1,2)+Math.pow(2,2)+Math.pow(4,2)+Math.pow(8,2)+Math.pow(10,2);
        System.out.println("Sum of 1^2+2^2+4^2+8^2+10^2 is: "+sum);
        }
}

Thanks


January 10, 2011 at 3:24 PM

he Hello;

Below is the code :

public class Example1 {

public static void main(String[] args) {

    String str = "COMPUTER";

    for (int i = 1; i < str.length()+1; i++) {
        for (int j = 0; j < i; j++) {
            System.out.print(str.charAt(j) + " ");
        }
        System.out.println();
    }
}

}

Anuj Kumar


January 10, 2011 at 3:25 PM

Hey;

Below is the code for 2nd prog:

import java.util.Scanner;

public class Example2 { public static void main(String[] args) {

    int num;
    System.out.println("Enter interger no: ");
    Scanner scanner = new Scanner(System.in);
    num = scanner.nextInt();
    int pro = 1;
    while (num != 0) {
        pro *= (num % 10);
        num = num / 10;
    }
    System.out.println("Product of digits: " + pro);

}

}


January 10, 2011 at 3:28 PM

Hey;

Below is the code for Diamond Pattern;

public class Example3 {

public static void main(String[] args) {

    int iMin = 0, iMax = 6;
    int jMin = 0;
    int count = 0;
    int i, j, k, l;
    for (i = iMax; i &gt;= iMin; i--) {
        count++;
        for (j = jMin; j &lt; i; j++)
            System.out.print("  ");
        System.out.print("* ");
        for (k = 1; k &lt; count; k++)
            System.out.print("  ");
        for (l = 1; l &lt; count - 1; l++)
            System.out.print("  ");
        if (count &gt; 1)
            System.out.print("* ");
        System.out.println();
    }
    for (i = iMin; i &lt; iMax; i++) {
        count--;
        for (j = jMin; j &lt;= i; j++)
            System.out.print("  ");
        System.out.print("* ");
        for (l = 1; l &lt; count; l++)
            System.out.print("  ");
        for (l = 1; l &lt; count - 1; l++)
            System.out.print("  ");
        if (count &gt; 1)
            System.out.print("* ");
        System.out.println();
    }
}

}

I think this might be help full for you. :)

for the series one plzz specify more that it is series or just hard codes expression...

Anuj Kumar (Knapster)


January 10, 2011 at 5:47 PM

Hi Friend,

4)Try the following code:

public class PatternExample {
public static void main(String[] args) {
int num=3;
int p = num;
int q = 0;
for (int i = 0; i <= num; i++) {
for (int j = p; j>= 1; j-- )
System.out.print(" ");
p-=1;
for (int k = 1; k <= i; k++)
System.out.print ("* ");
System.out.println();
}
num-=1;
for (int i = 0; i<=num; i++) {
for (int j = num; j > i; j--)
System.out.print (" *");
System.out.println();
for (int k = 0; k <= q; k++)
System.out.print(" ");
q+=1;
}
}
}

Thanks


January 11, 2011 at 5:44 PM

check sum of alternate digit of number is palindrome or not?


January 12, 2011 at 3:03 PM

Hi Friend,

Try this:

import java.math.*;
import java.util.*;
class CheckSumIsPalindrome{
    public static void main(String[] args){
        Scanner input=new Scanner(System.in);
        System.out.print("Enter Number: ");
        BigInteger bi=input.nextBigInteger();
        int num = 0;
        String strSum = bi.toString();
        for(int i = 0;i < strSum.length(); i+=2){
        char ch=strSum.charAt(i);
        int n=Integer.parseInt(Character.toString(ch));
        num+=n;     
        }
        System.out.println("Sum of Alternate digits is: "+num);  
        int n = num;
        int reversedNumber=0;
        for (int i=0; i<=num; i++){
        int r=num%10;
        num=num/10;
        reversedNumber=reversedNumber*10+r;
        i=0;
   }
        if(n == reversedNumber){
        System.out.print("Number is palindrome!");
    }
        else{
        System.out.println("Number is not palindrome!");
        }
    }
}

Thanks

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