Fileupload in servlet

If we upload a file using servlet can it possible to put the uploaded file in any locationof the syatem(in D drive or in C drive)??? If any pls give the code..

Thanks in advance....

View Answers

July 26, 2011 at 12:45 AM

import java.util.*;
import java.io.*;
class Tokensex
{
    public static void main(String [] args)throws Exception
    {
        InputStream is= System.in;
        InputStreamReader ir=new InputStreamReader(is);
        BufferedReader br= new BufferedReader(ir);
        char [] ch= new char[600];
        int i=br.read(ch,0,ch.length);
        String st1= new String(ch,0,ch.length);
        int count=0;
        StringTokenizer st=new StringTokenizer(st1);
        while(st.hasMoreTokens())
        {
            String token=st.nextToken(" ");
            count ++;
        }
        System.out.println("total no of words are:" + count);
    }
};

July 26, 2011 at 10:16 AM

1)page.jsp:

<%@ page language="java" %>
<HTML>
<FORM ENCTYPE="multipart/form-data" ACTION="../UploadServlet" METHOD=POST>
<center>
<table border="0" bgcolor=#ccFDDEE>
<tr>
<center><td colspan="2" align="center"><B>UPLOAD THE FILE</B><center></td>
</tr>
<tr><td colspan="2" align="center">&nbsp;</td></tr>
<tr><td><b>Choose the file To Upload:</b></td>
<td><INPUT NAME="file" TYPE="file"></td>
</tr>
<tr><td colspan="2" align="center">&nbsp;</td></tr>
<tr><td colspan="2" align="center"><input type="submit" value="Send File"> </td></tr>
<table>
</center>
</FORM>
</HTML>

2)UploadedFiles.java:

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;

public class UploadServlet extends HttpServlet{ 
     public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException {
     response.setContentType("text/html");
     PrintWriter out = response.getWriter();

    String saveFile="";
    String contentType = request.getContentType();
    if((contentType != null)&&(contentType.indexOf("multipart/form-data") >= 0)){
    DataInputStream in = new DataInputStream(request.getInputStream());
    int formDataLength = request.getContentLength();
    byte dataBytes[] = new byte[formDataLength];
    int byteRead = 0;
    int totalBytesRead = 0;
    while(totalBytesRead < formDataLength){
    byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
    totalBytesRead += byteRead;
   }
    String file = new String(dataBytes);
    saveFile = file.substring(file.indexOf("filename=\"") + 10);
    saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
    saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
    int lastIndex = contentType.lastIndexOf("=");
    String boundary = contentType.substring(lastIndex + 1,contentType.length());
    int pos;
    pos = file.indexOf("filename=\"");
    pos = file.indexOf("\n", pos) + 1;
    pos = file.indexOf("\n", pos) + 1;
    pos = file.indexOf("\n", pos) + 1;
    int boundaryLocation = file.indexOf(boundary, pos) - 4;
    int startPos = ((file.substring(0, pos)).getBytes()).length;
    int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
    File ff = new File(saveFile);
    FileOutputStream fileOut = new FileOutputStream("C:/UploadedFiles/"+ff);
    fileOut.write(dataBytes, startPos, (endPos - startPos));
    fileOut.flush();
    fileOut.close();
    out.println("You have successfully upload the file:"+saveFile);
    Connection connection = null;
    String connectionURL = "jdbc:mysql://localhost:3306/test";
    ResultSet rs = null;
    PreparedStatement psmnt = null;
    FileInputStream fis;
    try{
    Class.forName("com.mysql.jdbc.Driver").newInstance();
    connection = DriverManager.getConnection(connectionURL, "root", "root");
    File f = new File(saveFile);
    psmnt = connection.prepareStatement("insert into file(file_data) values(?)");
    fis = new FileInputStream(f);
    psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length()));
    int s = psmnt.executeUpdate();
    if(s>0){
    System.out.println("Uploaded successfully !");
    }
    else{
    System.out.println("Error!");
    }
    }
    catch(Exception e){
        e.printStackTrace();
        }
    }
  }
}

July 26, 2011 at 10:17 AM

Sorry, the above servlet is saved with the name UploadServlet.java.

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