Java XML Parsing,Java XML Parser Sax,Get XML Element,XML Elements

Get XML Elements

In this section you will learn to develop a simple java program to get the names of all elements contained in the XML document .

Description of the program:

The following program teaches to parse the elements and retrieve their names, from a XML document.

Create a java file to retrieve the starting elements. When you run this program it asks for a XML document. This is used as a command line argument. If you don't enter any file, the program throws an exception displaying "java.lang.ArrayIndexOutOfBoundsException: 0 at XMLElements.main( XML Elements.java:17)".

The parse() method of SAXParser class reads the contents. The SAXParserFactory is a factory API that enables applications to configure and obtain a SAX parser to parse XML documents. The startElement() method retrieves all starting elements and prints them on the console. Whenever an error occurs it throws the SAXException.

<?xml version = "1.0" ?>
<Employee-Detail>

<Employee>
<Emp_Id> E-001 </Emp_Id>
<Emp_Name> Vinod </Emp_Name>
<Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>

<Employee>
<Emp_Id> E-002 </Emp_Id>
<Emp_Name> Amit </Emp_Name>
<Emp_E-mail> Amit2@yahoo.com </Emp_E-mail>
</Employee>

<Employee>
<Emp_Id> E-003 </Emp_Id>
<Emp_Name> Deepak </Emp_Name>
<Emp_E-mail> Deepak3@yahoo.com </Emp_E-mail>
</Employee>

</Employee-Detail>


import javax.xml.parsers.*;

import org.xml.sax.*;

import org.xml.sax.helpers.*;



public class XMLElements{

  public static void main(String[] args) {

    try{

      SAXParserFactory parserFact = SAXParserFactory.newInstance();

      SAXParser parser = parserFact.newSAXParser();

      System.out.println("XML Elements: ");

      DefaultHandler handler = new DefaultHandler(){

        public void startElement(String uri, String lName, 

                String ele, Attributes attributes)throws SAXException{

          //print elements of xml

          System.out.println(ele);

        }

      };

      parser.parse(args[0], handler);

    }

    catch (Exception e){

      e.printStackTrace();

    }

  }

}

Output of program:

C:\vinod\xml\comXML>javac XMLElements.java

C:\vinod\xml\comXML>java XMLElements Employee-Detail.xml
XML Elements:
Employee-Detail
Employee
Emp_Id
Emp_Name
Emp_E-mail
Employee
Emp_Id
Emp_Name
Emp_E-mail
Employee
Emp_Id
Emp_Name
Emp_E-mail

Current Comments

1 comments so far (post your own) View All Comments Latest 10 Comments:

GET XML ELEMENTS code is wrong.

the code should be like this.

package com;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class DemoParser{
public static void main(String[] args)throws IOException{
BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter XML file name:");
String xmlFile = bf.readLine();
try{
SAXParserFactory parserFact = SAXParserFactory.newInstance();
SAXParser parser = parserFact.newSAXParser();
System.out.println("XML Elements: ");
DefaultHandler handler = new DefaultHandler(){
public void startElement(String uri, String lName,
String ele, Attributes attributes)throws SAXException{
System.out.println(ele);
}
};
parser.parse(xmlFile, handler);
}
catch (Exception e){
e.printStackTrace();
}
}
}

Posted by sanjay kumar gupta on Monday, 10.8.07 @ 21:52pm | #32519

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