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Get XML Elements


In this section you will learn to develop a simple java program to get the names of all elements contained in the XML document .

Description of the program:

The following program teaches to parse the elements and retrieve  their names, from a  XML document.                                                                              

Create a java file to retrieve the starting elements. When you run this program it asks for a XML document. This is used as a command line argument. If  you don't enter any file, the program throws an exception displaying "java.lang.ArrayIndexOutOfBoundsException: 0 at XMLElements.main( XML Elements.java:17)". 

The parse() method of SAXParser class reads the contents. The SAXParserFactory  is a factory API that enables applications to configure and obtain a SAX  parser to parse XML documents. The startElement() method retrieves all starting elements and prints them on the console. Whenever an error  occurs  it throws the SAXException.  

Here is the XML File: Employee-Detail.xml

<?xml version = "1.0" ?>

<Emp_Id> E-001 </Emp_Id>
<Emp_Name> Vinod </Emp_Name>
<Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>

<Emp_Id> E-002 </Emp_Id>
<Emp_Name> Amit </Emp_Name>
<Emp_E-mail> Amit2@yahoo.com </Emp_E-mail>

<Emp_Id> E-003 </Emp_Id>
<Emp_Name> Deepak </Emp_Name>
<Emp_E-mail> Deepak3@yahoo.com </Emp_E-mail>


Here is the Java File: XMLElements.java

import javax.xml.parsers.*;
import org.xml.sax.*;
import org.xml.sax.helpers.*;

public class XMLElements{
  public static void main(String[] args) {
      SAXParserFactory parserFact = SAXParserFactory.newInstance();
      SAXParser parser = parserFact.newSAXParser();
      System.out.println("XML Elements: ");
      DefaultHandler handler = new DefaultHandler(){
        public void startElement(String uri, String lName, 
            String ele, Attributes attributes
)throws SAXException{
          //print elements of xml
      parser.parse(args[0], handler);
    catch (Exception e){

Download this example 

Output of program:

C:\vinod\xml\comXML>javac XMLElements.java

C:\vinod\xml\comXML>java XMLElements Employee-Detail.xml
XML Elements:


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Current Comments

1 comments so far (post your own) View All Comments Latest 10 Comments:

GET XML ELEMENTS code is wrong.

the code should be like this.

package com;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class DemoParser{
public static void main(String[] args)throws IOException{
BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter XML file name:");
String xmlFile = bf.readLine();
SAXParserFactory parserFact = SAXParserFactory.newInstance();
SAXParser parser = parserFact.newSAXParser();
System.out.println("XML Elements: ");
DefaultHandler handler = new DefaultHandler(){
public void startElement(String uri, String lName,
String ele, Attributes attributes)throws SAXException{
parser.parse(xmlFile, handler);
catch (Exception e){

Posted by sanjay kumar gupta on Monday, 10.8.07 @ 21:52pm | #32519

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