XML Error Checking and Locating
In this section, you will learn how to check and locate
an error in the XML document and error position.
Description of program:
The following program helps you in checking and
locating an error in XML document.
Implementing this program you need a XML
document. When you run the following program then it asks a xml file name and
checks it. If the given file exists, the SAX Parser parses the XML document and
detects the error in it at the specified line and column by using the getLineNumber()
and getColumnNumber() methods. The getLineNumber method detects
line of error and the getColumnNumber method also detects column of error
and prints the line and column. If no any error in XML document, it will
show a message "Employee-Detail.xml is well-formed".
Whenever the given file doesn't exist, it displays "File not found!".
Here is the XML File: Employee-Detail.xml
<?xml version = "1.0" ?>
<Employee-Detail>
<Employee>
<Emp_Id> E-001 </Emp_Id>
<Emp_Name> Vinod </Emp_Name>
<Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>
<Employee>
<Emp_Id> E-002 </Emp_Id>
<Emp_Name> Amit </Emp_Name>
<Emp_E-mail> Amit2@yahoo.com </Emp_E-mail>
</Employee>
<Employe>
<Emp_Id> E-003 </Emp_Id>
<Emp_Name> Deepak </Emp_Name>
<Emp_E-mail> Deepak3@yahoo.com </Emp_E-mail>
</Employee>
</Employee-Detail> |
Here is the Java File: LocateError.java
import org.xml.sax.*;
import org.xml.sax.helpers.*;
import javax.xml.parsers.*;
import java.io.*;
public class LocateError{
public static void main(String[] args) throws IOException{
BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter XML file name:");
String xmlFile = bf.readLine();
LocateError par = new LocateError(xmlFile);
}
public LocateError(String str){
try{
File file = new File(str);
if (file.exists()){
XMLReader reader = XMLReaderFactory.createXMLReader();
reader.parse(str);
System.out.println(str + " is well-formed!");
}
else{
System.out.println("File not found: " + str);
}
}
catch (SAXParseException sax){
System.out.println(str + " isn't well-formed");
int line = sax.getLineNumber();
int col = sax.getColumnNumber();
System.out.println("Error is at line number "+ line + "
and Column position "+ col);
}
catch (SAXException sax){}
catch (IOException io){
System.out.println(io.getMessage());
}
}
}
|
Download this example.
Output of program:
C:\vinod\xml>javac LocateError.java
C:\vinod\xml>java LocateError
Enter XML file name:Employee-Detail.xml
[Fatal Error] Employee-Detail.xml:19:11: The end-tag for element type "Employe"
must end with a '>' delimiter.
Employee-Detail.xml isn't well-formed
Error is at line number 19 and Column position 11 |
|
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