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XML Well-Formed Verifier

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In this section we are going to develop a simple java program that determines whether a XML document is well-formed or not.

XML Well-Formed Verifier

     

In this section we are going to develop a simple java program that determines whether a  XML document is well-formed or not.

Description of the program:

In the following program, you will learn to parse a xml document and determine whether it is well-formed or not.    Develop a java file (SAXParserCheck.java) that uses a  xml file to parse and check its well-formedness. Initially the program checks that the given file exists or not by using exists() method. If the file exists then it will parse the xml file with the help of parse() method.

The XMLReaderFactory helps in creating an XML reader which parses  xml document using the appropriate callbacks. And it determines that the parsed xml is well-formed or not. If xml document is will-formed, it will display a message "Employee-Detail.xml is well-formed!" Otherwise prints "Employee-Detail.xml isn't well-formed!". If you enter a  file that doesn't exist it will show "File not found: Employee-Detail.xml".

Here is the XML File to be parsed: Employee-Detail.xml

<?xml version = "1.0" ?>
<Employee-Detail>

<Employee>
<Emp_Id> E-001 </Emp_Id>
<Emp_Name> Vinod </Emp_Name>
<Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>

<Employee>
<Emp_Id> E-002 </Emp_Id>
<Emp_Name> Amit </Emp_Name>
<Emp_E-mail> Amit2@yahoo.com </Emp_E-mail>
</Employee>

<Employee>
<Emp_Id> E-003 </Emp_Id>
<Emp_Name> Deepak </Emp_Name>
<Emp_E-mail> Deepak3@yahoo.com </Emp_E-mail>
</Employee>

</Employee-Detail>

Here is the code of Java File: SAXParserCheck.java

import org.xml.sax.*;
import org.xml.sax.helpers.*;
import java.io.*;

public class SAXParserCheck{

  public static void main(String[] argsthrows IOException{
  BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
  System.out.print("Enter XML file name:");
  String xmlFile = bf.readLine();
  SAXParserCheck par = new SAXParserCheck(xmlFile);
  }
  
  public SAXParserCheck(String str){
  try{
  File file = new File(str);
  if (file.exists()){
  XMLReader reader = XMLReaderFactory.createXMLReader();
  reader.parse(str);
  System.out.println(str + " is well-formed!");
  }
  else{
  System.out.println("File not found: " + str);
  }
  }
  catch (SAXException sax){
  System.out.println(str + " isn't well-formed");
  }
  catch (IOException io){
  System.out.println(io.getMessage());
  }
  }
}

Download this example 

Output of program:

C:\vinod\xml\comXML>javac SAXParserCheck.java

C:\vinod\xml\comXML>java SAXParserCheck
Enter XML file name:Employee-Detail.xml
Employee-Detail.xml is well-formed!

     

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Posted on: May 25, 2007

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