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Example to show Argument Exception in java
Posted on: October 22, 2008 at 12:00 AM

Here we are describing the use of using Argument exception in java .Exceptions are the way in Java to indicate to a calling method that an abnormal condition has occurred.

Example to show Argument Exception in java

In this Tutorial we explain an example from Argument exception in java .Exceptions are the condition in Java to indicate a calling method that an abnormal condition has occurred. This tutorial describes how to handle Argument exceptions appropriately in your programs. The steps involved in the program are described below:-

private static Scanner key = new Scanner(System.in):-Here we are declaring Scanner class object. Scanner is a class which is used to parse primitive types and strings using regular expressions.

Input = key. next():-This is the method by which we can find and returns the next complete token from this scanner.

System.out.println(Input + " is not an Integer value" + "\n"+ "Please enter appropriate value"):-This is the Exception message which is to be displayed if the number you entered is not a real number.

ArgumentException.java




import java.util.*;



public class ArgumentException {



  private static Scanner key = new Scanner(System.in);



  public static void main(String args[]) {

  int index;

  int i;

  String Input;



  for (index = 0; index < args.length; index++) {

  }



  System.out.print("Please enter a real number : ");

  Input = key.next();

  try {

  i = Integer.parseInt(Input);

  System.out.println("The value is " + i);

  } catch (NumberFormatException e) {

  System.out.println(Input + " is not an Integer value" + "\n" 

  + "Please enter apporipriate value");

  }

  }

}

Output of the program

Please enter a real number : Girish
Girish is not an Integer value
Please enter apporipriate value

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