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Example to show ArraylistException in Java
Posted on: October 23, 2008 at 12:00 AM
Here we are describing the use of using exception class in java .This tutorial describes how to handle Array list exceptions appropriately in your programs and designs.

Example to show ArraylistException in Java

     

Here we are describing the use of using exception class in java .This tutorial describes  how to handle Array list exceptions appropriately in your programs and designs. The steps involved in the program are described below:-

ArraylistException.java

import java.util.*;
public class ArraylistException {
  void buildAlphabet() {
  ArrayList list = new ArrayList();

  for (int i =1; i <=5; i++)
  {
  list.add(i,(String)("Girish"));
  }
  System.out.print("Elements of array are: " + list);
  }

  public static void main(String[] args) {
  ArraylistException ale=new ArraylistException();
  ale.buildAlphabet();
  }
}


Output of the program

Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 1, Size: 0
at java.util.ArrayList.add(ArrayList.java:367)
at ArraylistException.buildAlphabet(ArraylistException.java:11)
at ArraylistException.main(ArraylistException.java:18)
Java Result: 1

 
To avoid this error you have to give proper index for the List means to say starting index which is 0 for the array not 1.

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