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Example to show double exception in java

                         

The Tutorial describe you a code from double exception in java. The given below program tells about the occurrence of double exception. Double is a class that wraps a value of the primitive type double in an object. Double exception occurs in java when the string or primitive data type are not converted into a double value. The step involved in a program are described below - 

1)We have a class Double Exception, that include a main method. The main method include  -

Buffered Reader-  This read the text from the character stream

read line  ( ) - This is used to read a line of text.

to string( )  - This object  return you a string irrespective of any type of data type.

In case a user try to enter a string or primitive data type, that is not converted into a double, this causes the try block to cause exception in a code The exception subsequently handled by a catch block and show you a user defined message in the println.

Doubleexception.java


import java.lang.Math.*;

public class Doubleexception {

    public static void main(String args[]) {
        double c = 0;
        try {
            Double d = (500 100.9;
            c = d.intValue();
        catch (Exception e) {
            System.out.println(e.getMessage());
        }
        System.out.println("Value of c is: "+c);
    }
}

Output of the program

Value of c is: 4.0

Note:-if you will pass any number other than double type program will generate exception.

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