Example to show double exception in java

The Tutorial describe you a code from double exception in java. The given below program tells about the occurrence of double exception. Double is a class that wraps a value of the primitive type double in an object. Double exception occurs in java when the string or primitive data type are not converted into a double value. The step involved in a program are described below -

1)We have a class Double Exception, that include a main method. The main method include -

Buffered Reader- This read the text from the character stream

read line ( ) - This is used to read a line of text.

to string( ) - This object return you a string irrespective of any type of data type.

In case a user try to enter a string or primitive data type, that is not converted into a double, this causes the try block to cause exception in a code The exception subsequently handled by a catch block and show you a user defined message in the println.

Doubleexception.java




import java.lang.Math.*;



public class Doubleexception {



  public static void main(String args[]) {

  double c = 0;

  try {

  Double d = (500 / 100.9) ;

  c = d.intValue();

  } catch (Exception e) {

  System.out.println(e.getMessage());

  }

  System.out.println("Value of c is: "+c);

  }

}

Output of the program

Value of c is: 4.0

Note:-if you will pass any number other than double type program will generate exception.

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