Determining the largest number

This example of Java programming will teach you the
coding for determining the largest number amongst three. Here we have taken
three integers as x = 500, y = 70 and z = 3000. After defining these three
integers under the class "largernumber" apply "if" and
"else" conditions that can help you in finding the largest value one
by one.
First check if "x>y". If this
satisfies then check whether x>z or not. Again if this satisfies then write
in the system class that "x is greater". Again the term
"else" comes when "x" is not greater than "z". So
check again, if "z" is greater than "y" or not. If this
satisfies then type in the system class as "z is greater" otherwise
(in the else condition) "y" is greater. Now check whether
"y" is greater than "z" or not.
If "x" is not greater than
"y" as per the first condition, then the condition "else"
comes and now you have to check if "y>z" or not. If this satisfies
then the output comes as "y is greater".
Don't get confuse and analyze every condition
one by one and follow this example.
Here is the code of program:
class largernumber{
public static void main(String[] args) {
int x=500, y=70, z=3000;
if (x>y){
if (x>z){
System.out.println("x is greater");
}
else{
if(z>y){
System.out.println("z is greater");
}
else{
System.out.println("y is greater");
}
}
}
else{
if (y>z){
System.out.println("y is greater");
}
}
}
}
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