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To find first two maximum numbers in an array
2 Answer(s)      2 years and 2 months ago
Posted in : Java Beginners

Java program to find first two maximum numbers in an array,using single loop without sorting array.

December 27, 2011 at 12:11 PM

```import java.util.*;

class ArrayExample {
public static void main(String[] args) {
int secondlargest = 0;
int largest = 0;
Scanner input = new Scanner(System.in);
System.out.println("Enter array values: ");
int arr[] = new int[5];
for (int i = 0; i < arr.length; i++) {
arr[i] = input.nextInt();
if (largest < arr[i]) {
secondlargest = largest;
largest = arr[i];
}
if (secondlargest < arr[i] && largest != arr[i])
secondlargest = arr[i];
}
System.out.println("Largest number is: " + largest);
System.out.println("Second Largest number is: " + secondlargest);
}
}
```

September 10, 2012 at 2:36 PM

package com.java.interview.array;

import java.util.Scanner;

public class TwoLargestElementsOfArray {

```/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int secondlargest = 0;
int largest = 0;
int size = 0;
Scanner input = new Scanner(System.in);
System.out.println("Enter the size of array: ");
size = input.nextInt();
int arr[] = new int[size];
if (size < 2)
System.out.println("Please enter the valid size of array");
System.out.println("Enter array values: ");
for (int i = 0; i < arr.length; i++) {
arr[i] = input.nextInt();
if (largest < arr[i]) {
secondlargest = largest;
largest = arr[i];
}
if (secondlargest < arr[i] && largest != arr[i])
secondlargest = arr[i];
}
System.out.println("Largest number is: " + largest);
System.out.println("Second Largest number is: " + secondlargest);

}
```

}

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