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JPA setFirstResult Example

In this section, you will learn how to use setFirstResult method in your jpa application.

JPA setFirstResult Example


In this section, you will learn how to use setFirstResult method in your jpa application. The setFirstResult(N) method is used to skip the first "N"  elements form the result set. Please note that the counting starts from the 0, so if you specify 2 then first 3 records will be skipped.

setFirstResult(int startingPosition): This is the method of Query interface. The setFirstResult method is used to set the position of first result for retrieving the data. It also return  same query instance. 

For this application you need the following files:

  1. Database Table: student
  2. Model Class:
  3. Main Class:

Database Table: student

CREATE TABLE `student` ( 
`id` int(11) NOT NULL auto_increment, 
`sname` varchar(100) NOT NULL, 
`sroll` int(11) NOT NULL, 
`scourse` varchar(10) NOT NULL, 

Model Class:


package roseindia;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.Table;

* @author Administrator

public class Student {

private int id;

* @return the id
public int getId() {
return id;

* @param id the id to set
public void setId(int id) { = id;

@Column(name="sname", length=100,nullable=false)
private String sname;

* @return the sname
public String getSname() {
return sname;

* @param sname the sname to set
public void setSname(String sname) {
this.sname = sname;

private int sroll;

* @return the sroll
public int getSroll() {
return sroll;

* @param sroll the sroll to set
public void setSroll(int sroll) {
this.sroll = sroll;

private String scourse;

* @return the scourse
public String getScourse() {
return scourse;

* @param scourse the scourse to set
public void setScourse(String scourse) {
this.scourse = scourse;


Main Class:




package roseindia;


import java.util.Iterator;

import java.util.List;


import javax.persistence.EntityManager;

import javax.persistence.EntityManagerFactory;

import javax.persistence.EntityTransaction;

import javax.persistence.Persistence;

import javax.persistence.Query;



* @author Administrator



public class JPASetFirstResult {



* @param args


public static void main(String[] args) {

// TODO Auto-generated method stub


EntityManagerFactory emf=Persistence.createEntityManagerFactory("jpa");

EntityManager em=emf.createEntityManager();


EntityTransaction entr=em.getTransaction();


Query query=em.createQuery("SELECT st FROM Student st");


List stuList=query.getResultList();

Iterator stuIterator=stuList.iterator();


Student st=(Student);














log4j:WARN No appenders could be found for logger

log4j:WARN Please initialize the log4j system properly.

Hibernate: select as id0_, student0_.scourse
as scourse0_, student0_.sname as sname0_, student0_.sroll
 as sroll0_ from student student0_

sname:Suman sroll:103 scourse:Suman

sname:Noor sroll:104 scourse:Noor


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  Reload Image
June 14, 2011
Example not complete

I see that the example does not include the configuration settings of persistence.xml which is a vital component for any starter in the JPA area the example is incomplete without the settings of persistence.xml and is also incomplete in what command line to run
July 4, 2011

example is goo i want this source code.
August 23, 2011

it helps me to learn jpa...
November 17, 2011

Hi while am try to run this program am getting this exception. Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named jpa at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at com.cognizant.Jpa.JPASetFirstResult.main(
Kevin Wright
December 9, 2012
Keep getting PersistenceException

Hi, I am trying your example, but keep getting: Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named jpa at javax.persistence.Persistence.createEntityManagerFactory( at javax.persistence.Persistence.createEntityManagerFactory( at com.mycompany.TestJPADemo.App.main(
January 3, 2013
java persistance api

thanks folks,it is very usefull to me