Java Error incompatible types occurred when a compiler found a variable and
expression whose data type is not compatible to perform an operation on them.
Understand with an Example
In this Tutorial we want to describe you a code that help you in
understanding the java error incompatible type. For this we have a class name
Incompatobletype.Inside the main method we declare a variable name roll num
and sec int and char data type. Checklist condition is used to evaluate
the expression. The assignment operator = is used to show you an incompatible
type error in java rather than using = = in assignment operator. The Java
Compiler show an error in the assignment operator printed by System.out.println.
Incompatitabletype.java
public class Icompatobletype {
public static void main(String[] args) {
int rollnum = 76;
char sec;
if (rollnum = 90) {
sec = 'A';
} else {
sec = 'B';
}
System.out.println("Section with this rollno is: = " + sec);
}
}
|
Output
Compiling 1 source file to /home/girish/NetBeansProjects/errors/build/classes
/home/girish/NetBeansProjects/errors/src/Icompatobletype.java:8: incompatible types
found : int
required: boolean
if (rollnum = 90) {
1 error
BUILD FAILED (total time: 0 seconds)
|
To resolve this error give if (rollnum = =90)instead of if (rollnum = 90)
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