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hibernate by example

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In this tutorial you will learn hibernate by example with ready made downloadable source code.

hibernate by example

In this tutorial you will learn hibernate by example with ready made downloadable source code.

Here I am giving an example which will demonstrate you how can you make your application using Hibernate 4. To create an application I will use Eclipse IDE ( to see the basic requirement before creating an application with Hibernate 4 click here ).

Example :

Following steps that I have followed to create an application. These are as follows :

Step 1 : At first I have created a table named person in MySQL.

CREATE TABLE `person` ( 
`Id` int(10) NOT NULL, 
`Name` varchar(15) default NULL, 
PRIMARY KEY (`Id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 

Step 2 : Created a Java Project named coreHibernateExample (you can give the name as you wish).

File -> New -> project / Java Project -> giveProjectName -> Finish (in this example I have given coreHibernateExample).

Step 3 : Add the Hibernate jar files (to see how to add Hibernate's jar files click here )

Step 4 : Created a package named roseindia (you can give the name as you wish) under the src folder.

Select src -> Right Click ->New -> package -> givePackageName -> Finish (in this exmaple I have given roseindia).

Ste 5 : Created a file by following the name convention hibernate.cfg.xml (mandatory ) file under the src folder that the hibernate utilize to create a connection pool and the required environment setup.

Select src -> Right Click -> New -> File ->hibernate.cfg.xml -> Finish.

<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://192.168.10.13:3306/data
</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">root</property>
<property name="hibernate.connection.pool_size">10</property>
<property name="show_sql">true</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.current_session_context_class">thread</property>

</session-factory>
</hibernate-configuration>

Step 6 : Created a POJO class (persistent class) named Person.java in the package roseindia.

package roseindia;

public class Person
{
int id;
String name;
public Person()
{ 
}
public Person(int id, String name) {
super();
this.id = id;
this.name = name;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}

Step 7 : Crated a file named ( you may follow the naming convention ClassName.hbm.xml )  person.hbm.xml under the src folder to map a Person Object to the database table named person

<?xml version='1.0'?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">

<hibernate-mapping package="roseindia">
<class name="Person" table="person">
<id name="id" type="int" column="Id" >
<generator class="assigned"/>
</id>

<property name="name">
<column name="Name" />
</property>

</class>
</hibernate-mapping>

Step 8 : Developed a code by writing a java class named PersonDetail in the package roseindia which will persist the Person object in the person table.

package roseindia;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
import org.hibernate.service.ServiceRegistry;
import org.hibernate.service.ServiceRegistryBuilder;

public class PersonDetail
{
private static SessionFactory sessionFactory;
private static ServiceRegistry serviceRegistry;

public static void main(String[] args)
{
Session session = null;
try 
{
try
{
Configuration cfg = new Configuration().addResource(
"person.hbm.xml").configure();
serviceRegistry = new ServiceRegistryBuilder().applySettings(
cfg.getProperties()).buildServiceRegistry();
sessionFactory = cfg.buildSessionFactory(serviceRegistry);
}
catch (Throwable ex)
{
System.err.println("Failed to create sessionFactory object."+ ex);
throw new ExceptionInInitializerError(ex);
}
session = sessionFactory.openSession();

Person person = new Person();
System.out.println("Inserting Record");
Transaction tx = session.beginTransaction();
person.setId(1);
person.setName("Roseindia");
session.save(person);
tx.commit();
System.out.println("Done");
} catch (Exception e) {
System.out.println(e.getMessage());
} finally {
session.close();
}
}
}

Execute the example : You can execute the application as follows

Go to your PersonDetail class Right Click -> Run As -> Java Application or,

Select from the menu bar tab Run -> Run or,

press the Ctrl button along with f11 i.e. CTRL + f11.

Output :

When you will run the application output will be as follows :

1. On console of Eclipse the output will be displayed as :

2. After Successfully execution of the code the record will be saved to the table that you had created in MySQL. as :

Download Source Code

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Posted on: May 17, 2012

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