ARRAYS SORTING
Posted in : Java Interview Questions
How To Sort An Array With Out Using Sort Method ?I Want Code?

January 3, 2010 at 1:06 AM

Hi,
Here is the code in java. You can find both Ascending and Descending order code. Ascending order is commented.

public class ArraySort {

public static void main(String[] args) {
int a[] = {6,500,700,200,1000,1};
int temp=0;
/*** Descending Order***/
for(int i=0;i<a.length;i++)
{
for(int j=0;j<a.length;j++)
{
if(a[i]>a[j]){
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
/*** Ascending Order ***/
/*for(int i=0;i<a.length;i++)
{
for(int j=a.length-1;j>i;j--)
{
if(a[i]>a[j]){
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}*/
for(int i=0;i<a.length;i++)
System.out.println("a["+i+"] = "+a[i]);
}

}

Output:
a[0] = 1000
a[1] = 700
a[2] = 500
a[3] = 200
a[4] = 6
a[5] = 1

Regards,
javaquest2010.

January 4, 2010 at 10:51 AM

Hi Friend,

Try the following code:

public class SortArrayWithoutUSingMethod{
public static void sortArray(int array[], int len){
for (int i = 1; i < len; i++){
int j = i;
int tmp = array[i];
while ((j > 0) && (array[j-1] > tmp)){
array[j] = array[j-1];
j--;
}
array[j] = tmp;
}
}
public static void main(String a[]){
int i;
int array[]={7,2,9,6,4,8,3,1};
sortArray(array, array.length);
System.out.println("Sorted Array is: ");
for(i = 0; i <array.length; i++){
System.out.println(array[i]);
}
}

}

Thanks

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