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suneel
Problem in running first hibernate program....
6 Answer(s)      5 years ago
Posted in : Hibernate



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July 28, 2009 at 11:47 AM


Hi Friend,

It seems that your class has not been found.There may be problem in your directory structure or your class has not been in the defined package. Check it.Even if the error occurs,send the directory structure of your application.

Thanks


July 28, 2009 at 10:54 PM


Hi friend!I haven't changed the source code given in the zip file.The source code of FirstExample.java is as follows
----------------------------------------------------------------------------

package roseindia.tutorial.hibernate;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;


/**
* @author Deepak Kumar
*
* http://www.roseindia.net
* Hibernate example to inset data into Contact table
*/
public class FirstExample {
public static void main(String[] args) {
Session session = null;

try{
// This step will read hibernate.cfg.xml and prepare hibernate for use
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
session =sessionFactory.openSession();
//Create new instance of Contact and set values in it by reading them from form object
System.out.println("Inserting Record");
Contact contact = new Contact();
contact.setId(6);
contact.setFirstName("Deepak");
contact.setLastName("Kumar");
contact.setEmail("deepak_38@yahoo.com");
session.save(contact);
System.out.println("Done");
}catch(Exception e){
System.out.println(e.getMessage());
}finally{
// Actual contact insertion will happen at this step
session.flush();
session.close();

}

}
}

---------------------------------------------------------------------------
The module directory structure is as folows...
---------------------------------------------------------------------------
->hibernate(module name)
->lib
->net.roseindia.test
->net.roseindia.tutorial.hibernate
->roseindia.tutorial.hibernate
->Book.java
->Contact.java
->FirstExample.java
......
->Referenced libraries
->ant-1.6.2.jar
->ant-antlr-1.6.2.jar
->ant-junit-1.6.2.jar
->ant-launcher-1.6.2.jar
->ant-swing-1.6.2.jar
->antlr-2.7.4.jar
->c3p0-0.8.5.jar
->cglib-full-2.0.2.jar
->cleanimports.jar
->commons-collections-2.1.1.jar
->commons-logging-1.0.4.jar
->concurrent-1.3.2.jar
->connector.jar
->dom4j-1.5.2.jar
->ehcache-1.1.jar
->hibernate3.jar
->jaas.jar
->jacc-1_0-fr.jar
->jaxen-1.1-beta-4.jar
->jboss-cache.jar
->jboss-common.jar
->jboss-jmx.jar
->jboss-remoting.jar
->jboss-system.jar
->jdbc2_0-stdext.jar
->jgroups-2.2.7.jar
->jta.jar
->junit-3.8.1.jar
->log4j-1.2.9.jar
->mysql-connector-java-3.0.16-ga-bin.jar
->mysql-connector-java-3.1.6-bin.jar
->oscache-2.1.jar
->proxool-0.8.3.jar
->swarmcache-1.0rc2.jar
->versioncheck.jar
->xerces-2.6.2.jar
->xml-apis.jar
->JRE system libraries[JRE1.6.0_01]
->contact.hbm.xml
->hibernate.cfg.xml
--------------------------------------------------------------------------
Can u figure out where did i go wrong?Thanks in advance..!


July 29, 2009 at 5:47 PM


Hi Friend,

Try the following code:'FirstExample.java'

package roseindia.tutorial.hibernate;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;

public class FirstExample {
public static void main(String[] args) {
Session session = null;
Transaction tx=null;
try{

// This step will read hibernate.cfg.xml and prepare hibernate for use
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
session =sessionFactory.openSession();
//Create new instance of Contact and set values in it by reading them from form object
System.out.println("Inserting Record");
Contact contact = new Contact();
contact.setFirstName("anusmita");
contact.setLastName("singh");
contact.setEmail("anu@yahoo.com");
contact.setId(3);
tx = session.beginTransaction();
session.save(contact);
tx.commit();
System.out.println("Done");
System.exit(0);
}catch(Exception e){
System.out.println(e.getMessage());
}finally{

session.flush();
session.close();

}

}
}

Thanks


July 31, 2009 at 2:20 AM


I have changed to galileo and used your code.It just worked fine.Thanks man..!But I got a message as below.What does that mean?Is it a harmful message?
-----------------------------------------------------------------------

Hibernate: insert into CONTACT (FIRSTNAME, LASTNAME, EMAIL, ID) values (?, ?, ?, ?)

------------------------------------------------------------------------
Thanks,I am a complete newbie to hibernate.It may be a petty thing to ask...


January 7, 2011 at 7:33 PM


First thing you need to check is that your eclipse version should have the necessary hibernate plugins, switching to galileo might have worked because it might had the necessary hibernate plugins, also secondly you should check the hibernate.cfg.xml file, in that file the user should be set to "root" and the password should be set to your current mysql "password", remember that their is hibernate.cfg.xml in bin folder also, also check if you have installed proper JDBC for mysql database. --Alok Dethe



July 22, 2011 at 3:06 AM


Hibernate: insert into CONTACT (FIRSTNAME, LASTNAME, EMAIL, ID) values (?, ?, ?, ?). dont get confusion internally hibernate generated hql query for inserting data dynamically. mean like preparedstatement we pass our user input for every Questionmark.same like that dynamically,runtime,user entered input inserted in the place of '?" mean dynamic what u enter that will insert whether input coming from webpage or hotcode mean user passed in main method instead of webpage.



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