QuestionAsk Questions?
kodesudheer
If we upload a file using servlet can it possible to put the uploaded file in any locationof the syatem(in D drive or in C drive)??? If any pls give the code..
Thanks in advance....
View Answers
July 26, 2011 at 12:45 AM
import java.util.*;
import java.io.*;
class Tokensex
{
public static void main(String [] args)throws Exception
{
InputStream is= System.in;
InputStreamReader ir=new InputStreamReader(is);
BufferedReader br= new BufferedReader(ir);
char [] ch= new char[600];
int i=br.read(ch,0,ch.length);
String st1= new String(ch,0,ch.length);
int count=0;
StringTokenizer st=new StringTokenizer(st1);
while(st.hasMoreTokens())
{
String token=st.nextToken(" ");
count ++;
}
System.out.println("total no of words are:" + count);
}
};
July 26, 2011 at 10:16 AM
1)page.jsp:
<%@ page language="java" %> <HTML> <FORM ENCTYPE="multipart/form-data" ACTION="../UploadServlet" METHOD=POST> <center> <table border="0" bgcolor=#ccFDDEE> <tr> <center><td colspan="2" align="center"><B>UPLOAD THE FILE</B><center></td> </tr> <tr><td colspan="2" align="center"> </td></tr> <tr><td><b>Choose the file To Upload:</b></td> <td><INPUT NAME="file" TYPE="file"></td> </tr> <tr><td colspan="2" align="center"> </td></tr> <tr><td colspan="2" align="center"><input type="submit" value="Send File"> </td></tr> <table> </center> </FORM> </HTML>
2)UploadedFiles.java:
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class UploadServlet extends HttpServlet{
public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
String saveFile="";
String contentType = request.getContentType();
if((contentType != null)&&(contentType.indexOf("multipart/form-data") >= 0)){
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while(totalBytesRead < formDataLength){
byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
File ff = new File(saveFile);
FileOutputStream fileOut = new FileOutputStream("C:/UploadedFiles/"+ff);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
out.println("You have successfully upload the file:"+saveFile);
Connection connection = null;
String connectionURL = "jdbc:mysql://localhost:3306/test";
ResultSet rs = null;
PreparedStatement psmnt = null;
FileInputStream fis;
try{
Class.forName("com.mysql.jdbc.Driver").newInstance();
connection = DriverManager.getConnection(connectionURL, "root", "root");
File f = new File(saveFile);
psmnt = connection.prepareStatement("insert into file(file_data) values(?)");
fis = new FileInputStream(f);
psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length()));
int s = psmnt.executeUpdate();
if(s>0){
System.out.println("Uploaded successfully !");
}
else{
System.out.println("Error!");
}
}
catch(Exception e){
e.printStackTrace();
}
}
}
}
July 26, 2011 at 10:17 AM
Sorry, the above servlet is saved with the name UploadServlet.java.
Related Pages:
If you are facing any programming issue, such as compilation errors or not able to find the code you are looking for.
Ask your questions, our development team will try to give answers to your questions.
Tutorial Topics
