Home Answers Viewqa Java-Beginners how to create .exe file of java application??

 
 


raghvendra kumar
how to create .exe file of java application??
2 Answer(s)      3 years and 10 months ago
Posted in : Java Beginners

View Answers

July 30, 2009 at 10:05 AM


Hi Friend,

Try the following code:

import java.io.*;
import java.util.jar.*;

public class CreateJar {
public static int buffer = 10240;
protected void createJarArchive(File jarFile, File[] listFiles) {
try {
byte b[] = new byte[buffer];
FileOutputStream fout = new FileOutputStream(jarFile);
JarOutputStream out = new JarOutputStream(fout, new Manifest());
for (int i = 0; i < listFiles.length; i++) {
if (listFiles[i] == null || !listFiles[i].exists()|| listFiles[i].isDirectory())
System.out.println("-----------------------------------");
System.out.println("Adding " + listFiles[i].getName());
JarEntry addFiles = new JarEntry(listFiles[i].getName());
addFiles.setTime(listFiles[i].lastModified());
out.putNextEntry(addFiles);

FileInputStream fin = new FileInputStream(listFiles[i]);
while (true) {
int len = fin.read(b, 0, b.length);
if (len <= 0)
break;
out.write(b, 0, len);
}
fin.close();
}
out.close();
fout.close();
System.out.println("Jar File is created successfully.");
} catch (Exception ex) {}
}
public static void main(String[]args){
CreateJar jar=new CreateJar();
File folder = new File("c://Answers//Database";);
File[] files = folder.listFiles();
File file=new File("C://Answers//DataBase//DataBaseExamples.jar";);
jar.createJarArchive(file, files);
}

}

Thanks

June 22, 2012 at 12:35 AM


Thanks Dear,

I tested the program and it's running without any error ....

Pramoj









Related Pages:

Ask Questions?

If you are facing any programming issue, such as compilation errors or not able to find the code you are looking for.

Ask your questions, our development team will try to give answers to your questions.