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rose
Array
3 Answer(s)      6 years ago
Posted in : Java Beginners



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November 14, 2008 at 2:02 AM


Hi friend,


Code to solve the problem :

import java.io.*;

public class ArrayExample {
public static void main(String[] args) throws IOException {
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader bufReader = new BufferedReader(isr);
System.out.println("Press enter values");
String strAr[] = new String[5];
//System.out.println(strAr.length);
for(int i=0;i<strAr.length;i++)
{
strAr[i] = bufReader.readLine();
}
System.out.println("Press enter search value");
String strvar = bufReader.readLine();
boolean flag = false;
for(int i=0;i<strAr.length;i++)
{
if(strAr[i].equals(strvar))
{
flag= true;
}

}
if(flag)
{
System.out.println("Searched number found!");
}
else
{
System.out.println("Searched number not found!");
}

}
}

For more information on java visit to :

http://www.roseindia.net/java/

Thanks


November 14, 2008 at 3:58 AM


Hi ,


I hope that, this code will help you.


import java.io.*;
import java.util.*;

public class ArrayExamples {
public static void main(String[] args) throws IOException {

BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Press enter number!");
String strAr[] = new String[5];
for(int i=0;i<strAr.length;i++){
strAr[i] = buff.readLine();
}
System.out.println("Press enter search number!");
String strvar = buff.readLine();
boolean bool = false;
for(int i=0;i<strAr.length;i++){
if(strAr[i].equals(strvar)){
bool= true;
}
}
if(bool){
System.out.println("Searched number found" + ".");
}
else{
System.out.println("Searched number not found" + ".");
}
}
}

------------------------

Thanks.


November 14, 2008 at 4:41 AM


Hi,



import java.io.*;
import java.util.*;

public class SearchArrayDemo {
public static void main(String args[]) throws IOException {
BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
int array[] = {2, 5, -2, 6, -3, 8, 10, -7, -9, 4,15};
Arrays.sort(array);
int index = Arrays.binarySearch(array, 2);
System.out.println("Array list found in index " + index);
// Search for element not in array
index = Arrays.binarySearch(array, 1);
System.out.println("Array value not found in Index " + index);

int newIndex = -index - 1;

System.out.println("Press enter search number!");
int strvar = Integer.parseInt(buff.readLine());
boolean bool = false;
for(int i=0; i<array.length;i++){
if(array[i]==strvar){
bool= true;
}
}
if(bool){
System.out.println("Searched number found" + ".");
}
else{
System.out.println("Searched number not found" + ".");
}
}
private static void printArray(String message, int array[]) {
System.out.println(message + ": [length: " + array.length + "]");
// Print out sorted array elements
for (int i=0, n=array.length; i<n; i++) {
if (i != 0) System.out.print(", ");
System.out.print(array[i]);
}
System.out.println();
}

private static int[] insertElement(int original[], int element, int index) {
int length = original.length;
int dest[] = new int[length+1];
System.arraycopy(original, 0, dest, 0, index);
dest[index] = element;
System.arraycopy(original, index, dest, index+1, length-index);
return dest;
}
}

-------------------------

Thanks

Amardeep


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