
Possible to print the following (Using for Loops): 1. * **
2.*

specify the format properly.

*
**
***
****
*****
#include <stdio.h>
#include <conio.h>
void main(){
for(int i=1;i<=5;i++){
for(int j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
}
*****
****
***
**
*
#include <stdio.h>
#include <conio.h>
void main(){
for(int i=5;i>=1;i--){
for(int j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
}
*
**
***
****
*****
#include <stdio.h>
#include <conio.h>
void main(){
for(int i=1;i<=5;i++){
for (int j = 0; j < 5-i; j++){
printf(" ");
}
for(int j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
}
*****
****
***
**
*
#include <stdio.h>
#include <conio.h>
void main(){
for(int i=5;i>=1;i--){
for (int j = 0; j < 5-i; j++){
printf(" ");
}
for(int j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
}
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