Question: Case-insensitive equals using Hibernate Criteria.

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ratna rathor
Case-insensitive equals using Hibernate Criteria.
1 Answer(s)      4 years and 11 months ago
Posted in : Hibernate

How to use Case-insensitive equals with Hibernate Criteria?

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May 29, 2012 at 6:39 PM


The Case Insensitive ignores the case of the latter. It Selects all the records of the table related to the given parameters. Create hibernate configuration file (hibernate.cfg.xml) and save it in the same folder where you are going to save your source code.

Now create Persistent class Employee.java‚??Hibernate uses the Plain Old Java Object (POJO) classes to map to the database table. Next create an util class as HibernateUtil.java

Here is your MainClass-

package net.roseindia.main;
import java.util.*;
import net.roseindia.table.Employee;
import net.roseindia.util.HibernateUtil;
import org.hibernate.Criteria;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.criterion.Restrictions;

public class CaseInsensitiveEqual{
    public static void main(String[] args) {
    SessionFactory sessionFactory = HibernateUtil.getSessionFactory();
    Session session = sessionFactory.openSession();

    Criteria criteria = session.createCriteria(Employee.class);
    criteria.add(Restrictions.eq("name", "ron").ignoreCase());
    List<Employee> employeeList = new ArrayList<Employee>();
    employeeList = criteria.list();
    Iterator it = employeeList.iterator();
    while ( it.hasNext()) {
        Employee employee = (Employee) it.next();
        System.out.println(employee.getName());
    }
    session.close();
}
}

Description: Here

criteria.add(Restrictions.eq("name", "ron").ignoreCase());

Checks the property ‚??name‚?? for ‚??ron‚?? without caring the case.


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