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krishnarao
java
1 Answer(s)      6 years and 3 months ago
Posted in : Java Beginners



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August 11, 2008 at 5:01 PM


Hi friend,


Serialization is the process of saving an object in a storage medium (such as a file, or a memory buffer) or
to transmit it over a network connection in binary form.

The object to be serialized must implement java.io.Serializable class.

ObjectOutput ObjOut = new ObjectOutputStream(new FileOutputStream(f))

// Serialize an Object

import java.io.*;

public class ObjectSerialize{

public static void main(String[] args) throws IOException{
String str = "Hello World";
try {
// Serialize to a file
ObjectOutput objout = new ObjectOutputStream(new FileOutputStream("HelloWorld.ser"));
objout.writeObject(str);
objout.close();

// Serialize to a byte array
ByteArrayOutputStream baos = new ByteArrayOutputStream() ;
objout = new ObjectOutputStream(baos) ;
objout.writeObject(str);
objout.close();

// Get the bytes of the serialized object
byte[] buf = baos.toByteArray();
} catch (IOException e) {
}
}
}

//Deserialize the Object


import java.io.*;

public class ObjectDeserialize{
public static void main(String[] args) throws IOException{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter File name : ");
String file = in.readLine();
System.out.print("Enter extention : ");
String ext = in.readLine();
String filename = file + "." + ext;
File f = new File(filename);
try{
ObjectInputStream obj = new ObjectInputStream(new FileInputStream(f));
System.out.println("The text : "+ obj.readObject());
obj.close();
System.out.println("Deserializing Operation Completly Successfully.");
}
catch(ClassNotFoundException e){
System.out.println(e.getMessage());
}
catch(FileNotFoundException fe){
System.out.println("File not found ");
}
}
}

For read more information :

http://www.roseindia.net/java/example/java/io/SerializingObject.shtml



Thanks


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