
dear Sir/Mrs I'll be thankful for helping me on this .......
write a program that reads 10 numbers. find the largest number and count the occurrence of the largest number from a declared array. assume the assigned 4.6.3.2.5.6.6.1 and 6. the program will display the largest number os 6 and the count is 5.
note: 1-display the number in ascending order 2-display the number in descending order 3-display the total, average and the largest number

import java.util.*;
class ArrayExample12{
public static void main(String[] args){
int sum=0,count=0;
Scanner input=new Scanner(System.in);
System.out.println("Enter Array Elements: ");
int array[]=new int[10];
for(int i=0;i<array.length;i++){
int num=input.nextInt();
array[i]=num;
}
int maxValue = array[0];
for(int i=1;i < array.length;i++){
if(array[i] > maxValue){
maxValue = array[i];
}
}
for(int i=0;i<array.length;i++){
sum+=array[i];
if(array[i]==maxValue){
count++;
}
}
System.out.println("Sum Of Numbers is: "+sum);
System.out.println("Average of Numbers is: "+sum/array.length);
System.out.println("Largest No: "+maxValue+" which occurs "+count+" times.");
Arrays.sort(array);
System.out.println("Numbers in increasing order: ");
for(int i=0;i<array.length;i++){
System.out.println(array[i]);
}
System.out.println("Numbers in decreasing order: ");
for(int i=array.length-1;i>=0;i--){
System.out.println(array[i]);
}
}
}

Thank u very much ...... :)

could u put the "numbers in increasing order" and the "number in decreasing order" in one line ?? EX numbers in increasing order 1.2.3.4.5.6.7.8.9.10.