Constructing a File Name path in Java

In this section, you will learn about constructing a file name path through the java program.

Constructing a File Name path in Java

Constructing a File Name path 


In Java, it is possible to set dynamic path, which is helpful for mapping local  file name with the actual path of the file using the constructing filename path technique.

As you have seen, how a file is created to the current directory where the program is run. Now we will see how the same program constructs a File object from a more complicated file name, using the static constant File.separator or File.separatorCharto specify the file name in a platform-independent way. If we are using Windows platform then the value of this separator is  ' \ ' .

Lets see an example to create a file to the specified location.


public class PathFile{
  public static void main(String[] argsthrows IOException{
  File f;
  f=new File("example" + File.separator + "myfile.txt");
  System.out.println("New file \"myfile.txt\" 

has been created 
   to the specified location"
  System.out.println("The absolute path of the file is: "

Output of the program:


C:\nisha>java PathFile
New file "myfile.txt" has been created to the specified location
The absolute path of the file is: C:\nisha\example\myfile.txt


Download this Program

Another program set the dynamic path using File.separator given below:


public class ConstructingFileNamePath {
public static void main(String[] args){

    String filepath = File.separatorChar + "tapan"
+ File.separatorChar + "joshi";

    System.out.println("The path of the file is  :  " 
  + filepath

Output of the program:

C:\java>java ConstructingFileNamePath
The path of the file is : \tapan\joshi

Download this example.