i have hexa number "6a".
now to have it stored in int:...
its image problem of RGB format. now i have r=62,g=0,b=58( in hexa). therefore int should have 0x620058.
now if r=6a, g=00,b=50
int should be 0x6a0050.
When i do parseInt(integer.tohexstring()) it throws exception.
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