please give more explanation for the above example please give more explanation for the above example
Thank you very much for setting up the example and Thank you very much for setting up the example and sharing the code. I feel there may be some redundancy after the first else statement. Best Regards, Kim
ya this example is too good , but if it is some wh ya this example is too good , but if it is some what diffecult that will be better ok eny way thanks for this examples
please explain me about (string[] args) in the mai please explain me about (string[] args) in the main method
BEING FRIENDLY AM HAPPY THAT NOW I CAN DO JUST A BEING FRIENDLY AM HAPPY THAT NOW I CAN DO JUST A THING WITH JAVA.IT TAKES ME MORE THAN 3 WEEKS NOW TRYING TO UNDERSTAND WHAT WAS BEING TOUGHT BUT TODAY &I MEAN THIS DAY AM CAPABLE....KEEP ON HELPING US..THANX A LOT
If the task is display the largest number among 10 If the task is display the largest number among 100 integers, then what would be the solution, should we folow IF condition or Loop or something else please send the coding or the logic if anyone could solve this?
can we write a program in this way class greaternumber { public static void main(String[] args) { int x=100,y=200,z=12; if (x>y && y>z) { System.out.println("x is the Greater number"); } else if(z>x && z>y) { System.out.println ("Z is the larget numb
The code is good thanks a lot
any programmmers in above this program we are initiating no to variables other than this declare only variables and compare and they should read the values at compilation time ao simply what is the syntax for input of charater or nos.
This progrom does not work for all the values For example, If x = 2, y = 200 and z = 400 this program does not produce the output as it never compares y and z separately. I think another line of code should be added as in: class LargerNumber{ public static void main(String[] args) {
another example This is another type of example for finding the largest number. class velu1 { public static void main(String args[]) { int a=3,b=1,c=4; if (a>b && a>c) { System.out.println("a is greatest"); } else if (b>c && b>a) { System.out.println("b
Yeah How about between 6 or more numbers?
Compares the three numbers. class Largernumber { public static void main(String[] args) { int x=600, y=700, z=6100; if (x>y) { if (x>z) { System.out.println("x is greater"); } else { System.out.println("z is
Good This Program is Good but Add some Program of Thread also.
comment This is a wrong example! if Z>Y>X,can't get the result!
This may be excessive but it's certainly accurate! public class Comp3 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int x=1, y=2, z=3; if (x>y && x>z) { System.out.println("x is biggest"); } else if (y
if x is the smallest then it doesnt work there should be an else statment in the main else.. public static void main(String[] args) { int x=5,y=0,z=3; if(x>y) { if(x>z) System.out.println(x); else { if(z>y) System.out.println(z); else Sy
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last if-else seems not required Hi there in this program listed above i am sure the last if condition is not requiredwhen already checked greatness of "a" and "b" if they are not greatest the remaining intity "c" will automatically be the greatest. in place of this form of this lo
hi public static void main(String[] args) { int x=5,y=0,z=3; if(x>y) { if(x>z) System.out.println(x); else { if(z>y) System.out.println(z); } } else { if(y>z) System.out.println(y); else System.out.println(z); } }
Hello This is just for three integers, how about if we have ten or more integers?
largest No public class B{ public static void main (String args[]){ int a=50,b=40,c=30; if (a>b&&a>c){ System.out.println("a");} else if (b>a&&b>c) {System.out.println("b");} else{ System.out.println("c");} }}
c++ programming can you answer my question the using a while loop 10 numbers and display the largest among 10 numbers enter a number:10 enter a number:15 to the largest is 15
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explanation ; Hi,can I know what is the meaning for the above coding?I have find the explanation in internet,but not very clear about it. Thank you
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help please - Java Beginners example!"); int num = 100; Writer output = null; File file = new... types conversion example!"); int num = 100; BufferedWriter output = null...(); System.out.println("Your file has been written"); } } For more information
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