good example for the biginners
good example for the biginners 

Its very helpful for beginners.
Its very helpful for beginners. 

real leap years
Your leap year example gives false results for the years 1900, 2100 and others. The leap year rules are: 1. Years that are multiples of 4 are leap years, except for the following special years. 2. Years that are mutliples of 100 are not leap year 

Please Change The Program...
This Program Dose Not Meet All The Conditions For A Leap Year... 

Hi
Your leap year example gives false results for the years 1900, 2100 and others. The leap year rules are: 1. Years that are multiples of 4 are leap years, except for the following special years. 2. Years that are mutliples of 100 are not leap year 

Condition insufficient
this condition is not sufficient for century years.it shud also b divisible by 400 

wrong
The leap year is the year that is divided by the integer 4 and isn't divided by 100 or is divided by 400. So: if ((n%4==0 && n%100 != 0) || n%400 == 0){ System.out.println("The given year is a leap year"); } else{ System.o 

Best Site
this is best site for learn java progarmming... 

logic of leap year
function isLeapYear (year): if ((year modulo 4 is 0) and (year modulo 100 is not 0)) or (year modulo 400 is 0) then true else false  

There is error in your logic....
Hi, My name is Vishal...I think the logic you have given for leap year i.e. (year%4) is not enough to decide whether a year is leap year or not.... Because 1700, 1800, 1900 These are not leap years but still are divisible by 4.... Here is the  

help
Sir , I m student of software engneering plz help me to complete some project .or send some project sample kindly request student thnks ur student 

java tutorials
send me some more simple programs on my e-mail id ankitsre.jain08@gmail.com 

it worked with some modification
well this java code was a success though i had to modify it to suite my need of generating a given number of leap years ahead of the current year 

Checking whether a year is leap or not-Correction
public class Example { public void find(int n) { if((n%4==0&&n%100!=0)||(n%400==0)) { System.out.println("Leap Year") ; } else { System.out.println("Not Leap Year") ;  

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mahesh want to know java with good understanding
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solution, since the fundamental problem is that an array isn't really a good idea... i cannot solve this example 

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