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DOM Parser Example to Parse A DOM Document
Posted on: September 23, 2010 at 12:00 AM
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In this section, you will see how to parse a XML document in java.

DOM Parser Example to Parse A DOM Document

In this tutorial, we will discuss about how to parse(retrieve data) DOM Document.

The XML DOM views an XML document as a tree-structure. In this program, we read the XML file and print the data.

The steps are as follows:

Create an instance of DocumentBuilder using DocumentBuilderFactory. The DocumentBuilder object  parses the xml file to create a DOM object.

Get a list of Employee elements from the DOM and count the no of persons by getLength() of list.

For each employee element get the Name, ID  and Age and get the child nodes of every employee by using getChildNodes() and getNodeValues().

The xml file used for the Parsing is Employees.xml.

<?xml version="1.0" encoding="UTF-8"?>
<Roseindia>
  <Employee type="permanent">
        <Name>Ravi</Name>
        <Id>3</Id>
        <Age>28</Age>
   </Employee>
  <Employee type="contract">
        <Name>Rajesh</Name>
        <Id>4</Id>
        <Age>30</Age>
    </Employee>
  <Employee type="permanent">
        <Name>sanjeev</Name>
        <Id>5</Id>
        <Age>27</Age>
    </Employee>
</Roseindia>

The Read_PrintFile.java.

import java.io.File;
import org.w3c.dom.Document;
import org.w3c.dom.*;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException; 

public class Read_PrintXMLFile{
    public static void main (String argv []){
    try {
            DocumentBuilderFactory odbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder odb =  odbf.newDocumentBuilder();
            Document odoc = odb.parse (new File("Employees.xml"));
            odoc.getDocumentElement ().normalize ();
            System.out.println ("Root element of the doc is " + odoc.getDocumentElement().getNodeName());
            NodeList LOP = odoc.getElementsByTagName("Employee");
            int totalPersons =LOP.getLength();
            System.out.println("Total no of people : " + totalPersons);
            for(int s=0; s<LOP.getLength() ; s++)
        {

                Node FPN =LOP.item(s);
                if(FPN.getNodeType() == Node.ELEMENT_NODE)
          {
                    Element firstPElement = (Element)FPN;
                   
                    NodeList oNameList = firstPElement.getElementsByTagName("Name");
                    Element firstNameElement = (Element)oNameList.item(0);
                    NodeList textNList = firstNameElement.getChildNodes();
                    System.out.println("Name : " ((Node)textNList.item(0)).getNodeValue().trim());
                   
                    NodeList IDList = firstPElement.getElementsByTagName("Id");
                    Element IDElement = (Element)IDList.item(0);
                    NodeList textIDList = IDElement.getChildNodes();
                    System.out.println("Id : " ((Node)textIDList.item(0)).getNodeValue().trim());
                   
                    NodeList ageList = firstPElement.getElementsByTagName("Age");
                    Element ageElement = (Element)ageList.item(0);
                    NodeList textAgeList = ageElement.getChildNodes();
                    System.out.println("Age : " ((Node)textAgeList.item(0)).getNodeValue().trim());               
                }    //end of if clause
            }        //end of for loop with variable s
        }catch (SAXParseException err) {
        System.out.println (err.getMessage ());
        }catch (SAXException e) {
             e.printStackTrace ();
        }catch (Throwable t) {
        t.printStackTrace ();
        } 
    }
}

Output:

C:\>java Read_PrintXMLFile
Root element of the doc is Roseindia
Total no of people : 3
Name : Ravi
Id : 3
Age : 28
Name : Rajesh
Id : 4
Age : 30
Name : sanjeev
Id : 5
Age : 27

 Download the XML Code

Download the JAVA code/a>

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Posted on: September 23, 2010

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