Java count occurrence of number from array

Here we have created an example that will count the occurrence of numbers and find the number which has the highest occurrence. Now for this, we have created an array of 15 integers and accepted the numbers through the console. We have restricted to enter the number above 6, only (0-6 ) are allowed. If a number is not within this range, program will ask for another number. Then using the ArrayList we determined the occurrence of each element of the array.

Here is the code:

import java.util.*;

public class Search {
	public static void searchAndDisplay(int[] arr) {
		ArrayList list1 = new ArrayList();
		ArrayList list2 = new ArrayList();
		for (int element : arr) {
			int index = list1.indexOf(element);
			if (index != -1) {
				int newCount = list2.get(index) + 1;
				list2.set(index, newCount);
			} else {
				list1.add(element);
				list2.add(1);
			}
		}
		for (int i = 0; i < list1.size(); i++) {
			System.out.println("Number " + list1.get(i) + " occurs "
					+ list2.get(i) + " times.");

		}
		int maxCount = 0;
		int index = -1;
		for (int i = 0; i < list2.size(); i++) {
			if (maxCount < list2.get(i)) {
				maxCount = list2.get(i);
				index = i;
			}
		}
		System.out.println("Number " + list1.get(index)
				+ " has highest occurrence i.e " + maxCount);
	}

	public static void main(String[] args) {
		Scanner input = new Scanner(System.in);
		int[] arr = new int[15];
		System.out.println("Enter 15 integers (0-6):");
		for (int i = 0; i < arr.length; i++) {
			int num = input.nextInt();
			if (num <= 6 && num >= 0) {
				arr[i] = num;
			} else {
				System.out.print("Enter another number: ");
				num = input.nextInt();
			}
		}
		searchAndDisplay(arr);
	}
}

Output:

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