Mysql Like Operator
Mysql Like Operator is used to compare a part of string using the % wild card
character.
Understand with Example
The Tutorial illustrate an example from 'Mysql Like Operator'. This section of
tutorial lists records or rows from the table employee1 where like
column 'name' end with the character '%h'.
'%h' : The '%h' return the records from table where string end with
h character.
The create table helps you to create a table 'employee1' with required
fieldname and datatype.
Query to Create Table named employee1:
mysql>CREATE TABLE employee1 (
-> Empid int(10),
-> name varchar(60),
-> dob date
-> );
|
Query to insert data into Table named employee1:
Now we insert the records into table 'employee1'.
mysql>insert into employee1 values(01,'Girish','2008-12-20');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(02,'Komal','2008-12-21');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(03,'vineet','2008-12-21');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(04,'Amit','2008-12-20');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(02,'Komal','2008-12-23');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(02,'Sandeep','2008-12-24');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(02,'suman','2008-12-25');
Query OK, 1 row affected (0.02 sec)
mysql>insert into employee1 values(01,'AAA',' 2008-12-03');
Query OK, 1 row affected (0.02 sec)
|
Query to view data of Table named employee1:
mysql> select * from employee1;
+-------+---------+------------+
| Empid | Name | DOB |
+-------+---------+------------+
| 1 | Girish | 2008-12-20 |
| 2 | Komal | 2008-12-21 |
| 3 | vineet | 2008-12-21 |
| 4 | Amit | 2008-12-20 |
| 2 | Komal | 2008-12-23 |
| 2 | Sandeep | 2008-12-24 |
| 2 | suman | 2008-12-25 |
| 1 | AAA | 2008-12-03 |
+-------+---------+------------+
8 rows in set (0.00 sec)
|
Query to view data from Table named employee1 using like command:
The below Query is used to return the records from table 'employees' in which
name end with character '%h'.
mysql> select * from employee1
-> where name like '%h';
|
Output:-
+-------+--------+------------+
| Empid | Name | DOB |
+-------+--------+------------+
| 1 | Girish | 2008-12-20 |
+-------+--------+------------+
1 row in set (0.00 sec)
|
|
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