PHP SQL IF Statement
This example illustrates how to use the 'if' statement in php when
accessing the data from table in mysql database.
In this example we create a connection from database table using
mysql_connect("hostName", "userName", "Password").
After the connection created we choose database by
mysql_select_db("databaseName", connectionObject) and finally we
execute query by mysql_query("SELECT * FROM tableName").
mysql_fetch_array() returns an array corresponding to the fetched row. Here we are using the if
statement, so only one data will display here as shown in the output.
Source Code of IF_Statement.php
<?php
$con = mysql_connect("localhost","root","root");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("test", $con);
$result = mysql_query("SELECT * FROM emp");
echo "<table border='1'>
<tr>
<th>id</th>
<th>Name</th>
</tr>";
if($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
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Output:
Download Source Code
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