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convert system.out.print( p[ j ] +
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c programe
(){ for(int i=4;i>=1;i--){ for(int j=1;j<=i;j++){ printf("%d",j); } for(int j = 0; j < 5-i; j++){ printf(" "); } for(int j=i;j>=1;j
 
Boolean Expressions
: int k = 10; int j = 6; boolean b = true; Show what is printed by each... ); __________ System.out.println( b ); __________ System.out.println( k > j && j != 5 ); __________ System.out.println( j < k && k == 10
 
Boolean Expressions
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pyramid
++){ for (int j = 0; j < 4-i; j++){ System.out.print(" "); } for(int j=1;j<=i;j++){ System.out.print
 
pyramid
++){ for (int j = 0; j < 4-i; j++){ System.out.print(" "); } for(int j=1;j<=i;j++){ System.out.print
 
C Program to Print Pascal Triangle - Development process
void main(){ int a[15][15],i,j,rows,num=25,k; printf("\n enter the number of rows:"); scanf("%d",&rows); for(i=0;i=0;k--) printf(" "); for(j=0;j<=i;j++){ if(j==0||i==j){ a[i][j]=1; } else{ a[i][j]=a[i-1][j-1]+a[i-1][j
 
C Program - Development process
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Description
(String[] args){ int i,j,n=5; for(i=0;i<=n;i++) { System.out.println(); for(j=1;j<=n-i;j++) System.out.print(j); for(j=0;j<2*i;j++) System.out.print(" "); for(j=n-i;j>0;j--) System.out.print(j); } } } OUTPUT IS 1234554321
 
Description
(String[] args){ int i,j,n=5; for(i=0;i<=n;i++) { System.out.println(); for(j=1;j<=n-i;j++) System.out.print(j); for(j=0;j<2*i;j++) System.out.print(" "); for(j=n-i;j>0;j--) System.out.print(j); } } } OUTPUT IS 1234554321
 
Description
(String[] args){ int i,j,n=5; for(i=0;i<=n;i++) { System.out.println(); for(j=1;j<=n-i;j++) System.out.print(j); for(j=0;j<2*i;j++) System.out.print(" "); for(j=n-i;j>0;j--) System.out.print(j); } } } OUTPUT IS 1234554321
 
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(String[] args){ int i,j,n=5; for(i=0;i<=n;i++) { System.out.println(); for(j=1;j<=n-i;j++) System.out.print(j); for(j=0;j<2*i;j++) System.out.print(" "); for(j=n-i;j>0;j--) System.out.print(j); } } } OUTPUT IS 1234554321
 
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],b[2][2],c[2][2],i,j; clrscr(); printf("Enter the First matrix:\n"); for(i=0;i<2;i++) { for(j=0;j<2;j++){ scanf("%d",&a[i][j]); } } printf("\nThe First matrix is:\n"); for(i=0;i<2;i++) { printf("\n"); for(j=0;j<2;j
 
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); int j; int len = dimension; int number = 1; for (int i = 0; i < num; i++) { for (j = 0; j < len; j++) { spiralArray[i][i + j] = number++; } for (j = 1; j < len; j++) { spiralArray[i
 
c++
c++  Characterize the following algorithm in terms of Big-O notation. for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) for (int k = 1; k <= n; k++) cout << i + j + k
 
C Program to Print Stras - Development process
; int j=0; for(i=1;i<=4;i+=1){ printf("\n"); for(j=1;j<=i;j++) printf("*"); } printf("\n"); for(i=3;i>=0;i-=1){ for(j=0;j
 
Finding smallest value, then the next etc
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array problem
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problem
(in.readLine()); } for (int j=0;j>n;j++) { b[j]=Integer.parseInt(in.readLine()); } for( ;i<m && j<n; ) { if (a[i]< b[j]) { c[k]=a[j]; j++; k++; } else if (b[j]<a[i]) { c[k]=b[j]; j++; k++; } else if (a[i
 
HELP WITH ARRAY
[100]; int nItems=0; int j; int searchId; arr[0]= 11; arr[1...; for (j=0; j<nItems; j++) System.out.print(arr[j] + " "); System.out.println(" "); searchId = 66; for (j=0
 
PHP GD image grayscale
; $i++) { for ($j=0; $j<$imgh; $j++) { $rgb = ImageColorAt($im, $i, $j); $r[$i][$j] = ($rgb >> 16) & 0xFF; $g[$i][$j] = ($rgb >> 8) & 0xFF; $b[$i][$j] = $rgb & 0xFF; if ($r[$i][$j] == $g[$i][$j
 
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