In this example we are going to see how we can catch the exception ArrayIndexOutOfBoundException. ArrayIndexOutOfBoundException is thrown when we have to indicate that an array has been accessed with an illegal index.
Tutorial Details:
In this example we are going to see how we can catch the exception ArrayIndexOutOfBoundException. ArrayIndexOutOfBoundException is thrown when we have to indicate that an array has been accessed with an illegal index.
Suppose we have declared an array of int and the size of the array is 6, that means that this array can store six values. Now suppose if want to access the seventh variable which does not exist, then it will throws the exception ArrayIndexOutOfBound. It means that there is no other value instead after that we are forcing the array to give the next value.
Throwing an Exception
{
throw new ArrayIndexOutOfBoundsException
("Array...(ArrayIndexOutOfBoundsException e) {
out.println("<br><b>Exception message
Array Review
at 0.
Array subscription checks bounds. May throw ArrayIndexOutOfBoundsException...
vulnerabilities in C and C++, or ArrayIndexOutOfBoundsException in Java
Multiple try catch
(ArrayIndexOutOfBoundsException e) {
out.println("Array index out of bounds."
Exceptions - More
NullPointerException
or ArrayIndexOutOfBoundsException.
If you do... (ArrayIndexOutOfBoundsException e) {
}
Exceptions are so slow that this won't be faster unless...
instead of ArrayIndexOutOfBoundsException. The use of Exception
suggests
Exception Classes ArrayIndexOutOfBoundsException
Arrays index is not within
ArrayIndexOutOfBoundsException