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File Upload Servlet 3.0 Example

In this tutorial you will learn how to upload a file in servlet 3.0

File Upload Servlet 3.0 Example

In this tutorial you will learn how to upload a file in servlet 3.0

In this example I have used the @MultipartConfig annotation to upload the file. Earlier versions than the servlet 3.0 specification were not involves in handling the file upload.

By introducing the @MultipartConfig annotation in servlet 3.0 it can be possible now. When in any servlet if this annotaion is used it indicates that a servlet ask for request to conform multipart/form-data MIME type. This annotation has some optional elements. These are as follows :

  • fileSizeThreshold : It is represents the size of file in bytes that will be stored temporarily on disk.
  • location : It denotes a file location where you are required to store the files, path of file should be an absolute.
  • maxFileSize : It denotes the maximum size of a file that can be uploaded.
  • maxRequestSize : It denotes the size of a file that can be permitted for multipart/form-data requests.

In the example given below there are two methods getParts() and getPart(String name) is used. These two methods are newly added in HttpServletRequest interface.

  • getParts() : This method gives the all parts of a collection.
  • getPart(String name) : This method gives a part for a specified name.

In this example one more thing is used that is javax.servlet.http.Part interface. This interface has a method named write(String fileName) which writes the file with given name and it also allows for accessing the information such as headers, file size, content type.

Example :


<p>File Upload Example</p>
<form action="FileUploadServletExample" enctype="multipart/form-data" method="POST">
<input type="file" name="file1"><br>
<input type="Submit" value="Upload File"><br>

package roseindia.ServletFileUpload;
import java.util.Collection;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.Part;

public class FileUploadServletExample extends HttpServlet {

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
ServletContext context= getServletContext();
RequestDispatcher rd= context.getRequestDispatcher("/WEB-INF/fileUpload.html");
rd.forward(request, response);

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
PrintWriter out = response.getWriter();

Collection<Part> parts = request.getParts();

out.write("<h2> Total parts : "+parts.size()+"</h2>");

for(Part part : parts) {
printPart(part, out);

private void printPart(Part part, PrintWriter pw) {
StringBuffer strbuffer = new StringBuffer();
strbuffer.append("File Name : "+part.getName());
strbuffer.append("Content Type : "+part.getContentType());
strbuffer.append("File Size : "+part.getSize());
for(String header : part.getHeaderNames()) {
strbuffer.append(header + " : "+part.getHeader(header));


Output :

When you will execute the above example you will get the output as :

When you will click on "Browse" button or in the text box a dialog box will be open like as :

After then you can select your file which you want to upload like I am selected here as :

At last when you will click on "Upload File" button the information of uploaded file will be displayed as :

Download Source Code



Posted on: December 22, 2011 If you enjoyed this post then why not add us on Google+? Add us to your Circles

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  Reload Image
salvatore tramonte
August 16, 2012
Good Hint

I'm starting in studing web development, I've one question, how could I use relative path to upload image in a subfolder of my project so, when I'll deploy, I won't have any problem with absolute path? thank you in advance