Determining If a Year is a Leap Year in Java

This section determines whether the given year is leap year or not using the isLeapYear(year) method of the Calendar class.


 

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Determining If a Year is a Leap Year in Java

     

Leap Year: Leap Year is the year contains an extra day. In the leap year, February month contains 29 days since normally February month has 28 days. The year which is completely divided by 4 that is the leap year.

This section determines whether the given year is leap year or not using the isLeapYear(year) method of the Calendar class.

Calendar.isLeapYear(year):
This method returns a boolean value true, if the year is leap year otherwise it returns the boolean value false.

This program checks each and every entries properly.

Here is the code of the program:

import java.util.*;
import java.io.*;

public class LeapYear{
  public static void main(String[] argsthrows IOException{
  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
  System.out.print("Enter year to check for leap year : ");
  int year;
  try{
  year = Integer.parseInt(in.readLine());
  if(year < 1900 || year > 2100){
  System.out.print("Please enter a year less than 2101 and greater than 1899.");
  System.exit(0);
  }
  GregorianCalendar cal = new GregorianCalendar();
  if(cal.isLeapYear(year))
  System.out.print("Given year is leap year.");
  else
  System.out.print("Given year is not leap year.");
  }
  catch(NumberFormatException ne){
  System.out.print(ne.getMessage() " is not a legal entry.");
  System.out.println("Please enter a 4-digit number.");
  System.exit(0);
  }
  }
}

Download this example.

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Comments:1
Hasan rabbani
July 16, 2012
Leap Year of Java program

Discuss: Determining If a Year is a Leap Year in Java

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