Determining If a Year is a Leap Year in Java
Leap Year: Leap Year is the year contains an
extra day. In the leap year, February month contains 29 days since normally February
month has 28 days. The year which is completely divided by 4 that is the leap
year.
This section determines whether the given year is leap
year or not using the isLeapYear(year) method of the Calendar
class.
Calendar.isLeapYear(year):
This method returns a boolean value true, if the year is leap year
otherwise it returns the boolean value false.
This program checks each and every entries properly.
Here is the code of the program:
import java.util.*;
import java.io.*;
public class LeapYear{
public static void main(String[] args) throws IOException{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter year to check for leap year : ");
int year;
try{
year = Integer.parseInt(in.readLine());
if(year < 1900 || year > 2100){
System.out.print("Please enter a year less than 2101 and greater than 1899.");
System.exit(0);
}
GregorianCalendar cal = new GregorianCalendar();
if(cal.isLeapYear(year))
System.out.print("Given year is leap year.");
else
System.out.print("Given year is not leap year.");
}
catch(NumberFormatException ne){
System.out.print(ne.getMessage() + " is not a legal entry.");
System.out.println("Please enter a 4-digit number.");
System.exit(0);
}
}
}
|
Download this example.
|
Del.icio.us
Digg
Google
Spurl
Blink
Furl
Simpy
Y! MyWeb
Current Comments
0 comments so far (post your own) View All Comments Latest 10 Comments: