Home Java Example Java Util Escaping Special Characters in a Pattern



Escaping Special Characters in a Pattern
Posted on: February 22, 2008 at 12:00 AM
This section illustrates you how to escape all special characters from the given string or text. Here, you can learn the way of detecting all special characters present in the given string.

Escaping Special Characters in a Pattern

     

This section illustrates you how to escape all special characters from the given string or text. Here, you can learn the way of detecting all special characters present in the given string.

Program Result:

This section provides an example for the best illustration about the way of matching special characters in the given string or text. This program finds special characters and replaces all the detected special characters by "F" character and display whole string with the "F" character place of any special characters in the given string or text.

Code Description:

Pattern.compile("[^a-zA-Z0-9 ]"):
This method compiles a regular expression "[^a-zA-Z0-9 ]" which does not detects a to z, A to Z and 0 to 9 characters, means it detects all special symbols or characters.

Here is the code of the program:

import java.util.regex.*;
import java.io.*;

public class EscapeSpecialChar{
  public static void main(String[] argsthrows IOException{
  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
  System.out.print("Enter string to find special characters: ");
  String string = in.readLine();
  Pattern pattern = Pattern.compile("[^a-zA-Z0-9]");
  Matcher matcher = pattern.matcher(string);
  String str = matcher.replaceAll("F");
  System.out.print(str);
  }
}

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