Constructing a File Name path
In Java, it is possible to set dynamic path, which is helpful for mapping
local file name with the actual path of the file using the constructing
filename path technique.
As you have seen, how a file is created to
the current directory where the program is run. Now we will see how the
same program constructs a File object from a more complicated
file name, using the static constant File.separator or File.separatorCharto
specify the file name in a platform-independent way. If we are using Windows platform then the value of this
separator is ' \ ' .
Lets see an example to create a file to the
specified location.
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import java.io.*;
public class PathFile{
public static void main(String[] args) throws IOException{
File f;
f=new File("example" + File.separator + "myfile.txt");
f.createNewFile();
System.out.println("New file \"myfile.txt\"
has been created
to the specified location");
System.out.println("The absolute path of the file is: "
+f.getAbsolutePath());
}
}
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Output of the program:
C:\nisha>javac PathFile.java
C:\nisha>java PathFile
New file "myfile.txt" has been created to the specified location
The absolute path of the file is: C:\nisha\example\myfile.txt
C:\nisha> |
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Another program set the dynamic path using File.separator
given below:
import java.io.*;
public class ConstructingFileNamePath {
public static void main(String[] args){
String filepath = File.separatorChar + "tapan"
+ File.separatorChar + "joshi";
System.out.println("The path of the file is : "
+ filepath);
}
}
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Output of the program:
C:\java>java ConstructingFileNamePath
The path of the file is : \tapan\joshi
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this example.
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