Hello Sir;
I just look your example's code.
In this sentence's : String str = in.readLine();
not correct.
Pls, in to br
This full sentence is : String str = br.readLine();
Thank you... :)
Hi there...pls help me as i m geting an error reading CHARACTER input from user...i m eting as problem in parsing d program !! pls reply asap !!
Getting these 2 errors -
Ccipher.java:53: cannot find symbol
symbol : variable Char
location: class Ccipher
pt[i]=Char.parseChar(stdin.readLine());
^
Ccipher.java:98: cannot find symbol
symbol : variable Char
location: class Ccipher
pt[i]=Char.parseChar(stdin.readLine());
^
2 errors
Their is Two error
1. Semicolon at the end of InputStreamReader inp = new InputStreamReader(System.in)
2. br.readLine() insted of in.readline()
String str = in.readLine();
In the example above instead of in.readLine(), it should be br.readLine().
String str = in.readLine();
should be replaced with
String str = br.readLine();
Hi Alexander,Nice trick invoking a sicrpt :)I think the problem is in this line of your ProcessBuilder params:> commands.add( \ image Over 0,0 0,0 im-watermark.png'\ ");If you re-write that as:> commands.add( image );> commands.add( Over );> commands.add( 0,0 );> commands.add( 0,0 );> commands.add( im-watermark.png ); it should work.
Your mistake code...Srun Kagna May 31, 2011 at 8:35 AM
Hello Sir; I just look your example's code. In this sentence's : String str = in.readLine(); not correct. Pls, in to br This full sentence is : String str = br.readLine(); Thank you... :)
Typo in program codeanonymous June 29, 2011 at 8:40 AM
in.readLine(); // Error , replace by the following br.readLine();
program code above! and i had made some changesTenzin Choeku October 18, 2011 at 11:53 AM
import java.io.*; public class ReadStandardIO{ public static void main(String[] args) throws IOException{ InputStreamReader inp = new InputStreamReader(System.in); BufferedReader br = new BufferedReader(inp); System.out.println("Enter text : "); String str = br.readLine(); System.out.println("You entered String : "); System.out.println(str); } }
JAVAJavaCoder November 16, 2011 at 2:19 PM
insted of this line > String str = in.readLine(); it should be > String str = br.readLine();
Bug in Read Text from Standard IO Example.Arun. December 13, 2011 at 12:17 PM
String str = in.readLine(); is wrong. Change it to String str = br.readLine();
typoSahi March 12, 2013 at 2:15 AM
String str = in.readLine(); => String str = br.readLine();
having problem in geting character input from userSarabjeet January 10, 2013 at 4:43 PM
Hi there...pls help me as i m geting an error reading CHARACTER input from user...i m eting as problem in parsing d program !! pls reply asap !! Getting these 2 errors - Ccipher.java:53: cannot find symbol symbol : variable Char location: class Ccipher pt[i]=Char.parseChar(stdin.readLine()); ^ Ccipher.java:98: cannot find symbol symbol : variable Char location: class Ccipher pt[i]=Char.parseChar(stdin.readLine()); ^ 2 errors
JavaGobinathan February 3, 2012 at 9:08 PM
Give me all possible input statements with example....
B.E.- Java Prof WorkingRajesh Kumar Patel February 7, 2012 at 4:05 PM
Their is Two error 1. Semicolon at the end of InputStreamReader inp = new InputStreamReader(System.in) 2. br.readLine() insted of in.readline() String str = in.readLine();
feedback relating to typing error in program..... amr April 5, 2012 at 4:55 PM
semi colon missing:InputStreamReader inp = new InputStreamReader(System.in) in is not valid object:String str = in.readLine();
This postSivan Mehta May 20, 2012 at 8:18 AM
The sample code you provided doesn't even compile. How is supposed to be used?
In the example one change is requiredPratik July 2, 2012 at 10:15 PM
In the example above instead of in.readLine(), it should be br.readLine(). String str = in.readLine(); should be replaced with String str = br.readLine();
question:ritika July 19, 2012 at 12:00 PM
1.how do we read a single character from keyboard??
CnrTEuUumCkxVMahmoud August 26, 2012 at 6:28 AM
Hi Alexander,Nice trick invoking a sicrpt :)I think the problem is in this line of your ProcessBuilder params:> commands.add( \ image Over 0,0 0,0 im-watermark.png'\ ");If you re-write that as:> commands.add( image );> commands.add( Over );> commands.add( 0,0 );> commands.add( 0,0 );> commands.add( im-watermark.png ); it should work.
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