Try this one.

1)roseindia.xml:

<?xml version="1.0" encoding="ISO-8859-1"?>

<roseindia>

  <employee>
    <name>A</name>
    <date-of-birth>01-02-80</date-of-birth>
  <city>Delhi</city>
  </employee>

  <employee>
    <name>B</name>
    <date-of-birth>02-02-80</date-of-birth>
  <city>Delhi</city>
  </employee>

  <employee>
    <name>C</name>
    <date-of-birth>03-02-80</date-of-birth>
  <city>Delhi</city>
  </employee>

  <employee>
    <name>D</name>
    <date-of-birth>04-02-80</date-of-birth>
  <city>Delhi</city>
  </employee>

  </roseindia>

2)ParseXML.java:

import org.w3c.dom.*;
import javax.xml.parsers.*;
public class ParseXML{
    public static boolean isTextNode(Node n){
    return n.getNodeName().equals("#text");
  }
    public static void main(String[]args)throws Exception{
  DocumentBuilderFactory docFactory = 
  DocumentBuilderFactory.newInstance();
  DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
  Document doc = docBuilder.parse("roseindia.xml");

          Element  element = doc.getDocumentElement(); 
          NodeList personNodes = element.getChildNodes();     
          for (int i=0; i<personNodes.getLength(); i++){
            Node emp = personNodes.item(i);
            if (isTextNode(emp))
              continue;
            NodeList NameDOBCity = emp.getChildNodes(); 

          for (int j=0; j<NameDOBCity.getLength(); j++ ){
            Node node = NameDOBCity.item(j);
            if ( isTextNode(node)) 
              continue;
       System.out.print(node.getFirstChild().getNodeValue()+"\t ");
          } 
          System.out.println();
          }
    }
}