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viwanshu vaibhaw
write a menu driven program to accept a number belonging to any number system that is octal,binary,decimal,hexadecimal according to user's choice and display its equivalent number system entered according to the user's choice
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December 2, 2010 at 4:27 PM
Hi Friend,
Try the following code:
<html>
<script>
function getNumber(){
var num=document.getElementById('num').value;
var type=document.getElementById('type').value;
var sel=window.prompt("Select Number System:\n1 for Octal\n2 for Binary\n3 for Decimal\n4 for Hexadeciaml");
sel=parseInt(sel);
switch(sel){
case 1:
if(type=="decimal"){
num=parseInt(num);
var octal = num.toString(8);
alert(octal);
}
else if(type=="octal"){
alert("Entered value is in octal!");
}
else if(type=="hexadecimal"){
var number=parseInt(num,16);
alert(number.toString(8));
}
else if(type=="binary"){
var number=parseInt(num,2);
alert(number.toString(8));
}
break;
case 2:
if(type=="decimal"){
num=parseInt(num);
var binary = num.toString(2);
alert(binary);
}
else if(type=="octal"){
var number=parseInt(num,8);
alert(number.toString(2));
}
else if(type=="hexadecimal"){
var number=parseInt(num,16);
alert(number.toString(2));
}
else if(type=="binary"){
alert("Entered values is in binary!");
}
break;
case 3:
if(type=="decimal"){
alert("Entered value is in decimal!");
}
else if(type=="octal"){
var number=parseInt(num,8);
alert(number);
}
else if(type=="hexadecimal"){
var number=parseInt(num,16);
alert(number);
}
else if(type=="binary"){
var number=parseInt(num,2);
alert(number);
}
break;
case 4:
if(type=="decimal"){
num=parseInt(num);
var hexadecimal = num.toString(16);
alert(hexadecimal);
}
else if(type=="octal"){
var number=parseInt(num,8);
alert(number.toString(16));
}
else if(type=="hexadecimal"){
alert("Entered value is in hexadecimal!");
}
else if(type=="binary"){
var number=parseInt(num,2);
alert(number.toString(16));
}
break;
default:
}
}
</script>
Enter Number <input type="text" id="num"><br><br>
Enter Type <input type="text" id="type"><sub>binary,octal,decimal,hexadecimal</sub><br><br>
<input type="button" onclick="getNumber();" value="Get">
</html>
Thanks
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