The above code can also be written as follows :

public class Test
{
   ArithmeticException ae;
   public int  divide(int numerator,int denominator)
    { 
       if(second==0)
          {
             throw ae;             
          }       
       return numerator/denominator;
    }
   public static void main(String[] args) 
    {
       Test test = new Test();
       test.ae = new ArithmeticException("Second Number must not be zero");

            int result = test.divide(4, 0);
            System.out.println(result);        
    }
}

hi friend, I think we can use the inbuilt exception variable with throw keyword in java.

I hope following sample code will be helpful for you.

public class Test
{
   static ArithmeticException ae;
   static int  divide(int first,int second)
    { 
       if(second==0)
          {
             throw ae;
          }        
       return first/second;
    }
   public static void main(String[] args) 
    {
       ae = new ArithmeticException("Second Number must not be zero");
       try
        {
            int result = divide(4, 0);
            System.out.println(result);
        }
      catch (Exception e) 
        {
           //e.printStackTrace();
           System.out.println(ae);
           //System.out.println(e);
        }
    }
}