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Raju
Integers from 0 to X stored in an array of size X+1. Each integer appears once & only once, but in random order e.g. Consider array of size 5 as below...
Arr[0]=3; Arr[1]=0; Arr[2]=1; Arr[3]=4; Arr[4]=2;
Process the above array as input & output an array where indices & values of the input array are flipped. e.g. Since 0th element of Arr contains 3, value of 3rd element in the output array should be 0. In short, Arr[0]=3 in the input, becomes Arr[3]=0 in the output.
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November 24, 2010 at 3:07 PM
Hello Friend,
Try the following:
class ArrayExample1{
public static void main(String[] args){
int Arr[]=new int[5];
Arr[0]=3;
Arr[1]=0;
Arr[2]=1;
Arr[3]=4;
Arr[4]=2;
for(int i=0;i<Arr.length;i++){
System.out.println("Arr["+Arr[i]+"]="+i);
}
}
}
Thanks
November 24, 2010 at 3:07 PM
Hello Friend,
Try the following:
class ArrayExample1{
public static void main(String[] args){
int Arr[]=new int[5];
Arr[0]=3;
Arr[1]=0;
Arr[2]=1;
Arr[3]=4;
Arr[4]=2;
for(int i=0;i<Arr.length;i++){
System.out.println("Arr["+Arr[i]+"]="+i);
}
}
}
Thanks
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