random numbers 1 Answer(s) 3 years ago
Posted in : Java Beginners
Hello i need this code to be modified for me to display the random numbers, but not twice or more. I mean i need a number to be display once. This code allows some numbers to be displayed more than once.
Hi Friend,
Try the following code:
import java.util.*; class RandomNumberExample { static Random generator = new Random(); public static int get (int[] array) { int rnd = generator.nextInt(array.length); return array[rnd]; } public static void main(String[]args){ int arr[]=new int[10]; Scanner input=new Scanner(System.in); System.out.println("Enter 10 numbers: "); for(int i=0;i<10;i++){ arr[i]=input.nextInt(); } System.out.println(); System.out.println("Random numbers are: "); int random[]=new int[5]; for(int i=0;i<random.length;i++){ random[i] = RandomNumberExample.get(arr); System.out.println(random[i]); } } }
Thanks
View Answers
June 30, 2010 at 4:17 PM
Hi Friend,
Try the following code:
import java.util.*;
public class RandomNumberExample { public static List<Integer> get(List<Integer> numbers, int noOfRandomNumbers) { List<Integer> list = new ArrayList<Integer>(numbers); List<Integer> randomList = new ArrayList<Integer>();
Random rd= new Random(); for (int i=0; i < noOfRandomNumbers; i++) { int index = (int) (rd.nextDouble()*list.size()); randomList.add(list.get(index)); list.remove(index); } return randomList; } public static void main(String[] args) { int arr[]=new int[10]; Integer in[] = new Integer[10]; Scanner input=new Scanner(System.in); System.out.println("Enter 10 numbers: "); for(int i=0;i<arr.length;i++){ arr[i]=input.nextInt(); in[i]=new Integer(arr[i]); } List<Integer> randomList = get(Arrays.asList(in),5); for (Integer randomNumber : randomList) { System.out.print(randomNumber + " "); } } }
Thanks
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